Epi*_*lol 3 php database arrays properties
我收到这个错误:
\nWarning: Attempt to read property "squadra" on array in C:\\xampp\\htdocs\\statistiche-calcio\\index.php on line 57\nRun Code Online (Sandbox Code Playgroud)\n这是我的 db.php 文件的代码:
\n <?php\n\nfunction connect($dbHost, $dbName, $dbUsername, $dbPassword){\n\n $db = new mysqli(\n $dbHost, \n $dbUsername, \n $dbPassword, \n $dbName\n );\n\n if($db->connect_error){\n die("Impossibile connettersi al database \\n" . $db->connect_error . "\\n" . $db->connect_errno);\n }\n return $db;\n}\n\n\nfunction fetchAll(mysqli $db, $table){\n\n $data = [];\n\n $sql = "SELECT * FROM $table";\n\n $results = $db->query($sql);\n\n if($results->num_rows > 0){\n while($row = $results->fetch_object()){\n $data[] = $row;\n }\n }\n return $data;\n}\n\n\n\nfunction fetchSquadra(mysqli $db, $table, $squadra){\n\n $data = [];\n\n $sql = "SELECT * FROM $table WHERE id = " . $squadra;\n\n $results = $db->query($sql);\n\n if($results->num_rows === 1){\n while($row = $results->fetch_object()){\n $data[] = $row;\n }\n \n }\n return $data;\n}\nRun Code Online (Sandbox Code Playgroud)\n这是我的index.php,我收到错误:
\n<?php\nrequire_once('config.php');\nrequire_once('db.php');\n\n$db = connect(\n DB_HOST, \n DB_NAME, \n DB_USERNAME, \n DB_PASSWORD,\n);\n\n$records = [];\n\n$records = fetchAll($db, 'partite');\n\n\n?>\n\n<!DOCTYPE html>\n<html lang="en">\n<head>\n <meta charset="UTF-8">\n <meta http-equiv="X-UA-Compatible" content="IE=edge">\n <meta name="viewport" content="width=device-width, initial-scale=1.0">\n <title>Document</title>\n</head>\n<body>\n <style>\n table, th, td{\n border: 1px solid grey;\n text-align: center;\n }\n </style>\n <h1>Risultati Premier League</h1>\n <table>\n <thead>\n <tr>\n <th>ID</th>\n <th>Data</th>\n <th>Casa</th>\n <th>Risultato</th>\n <th>Ospite</th>\n <th>Risultato 1 tempo</th>\n </tr>\n </thead>\n <tbody>\n <?php\n if(count($records) > 0):\n foreach($records as $record):\n $squadra_casa = fetchSquadra($db, 'squadre', $record->squadra_casa);\n $squadra_ospite = fetchSquadra($db, 'squadre', $record->squadra_ospite);\n \n ?>\n <tr>\n <td><?php echo $record->id;?></td>\n <td><?php echo $record->data;?></td>\n <td><?php echo $squadra_casa->squadra;?></td>\n <td><?php echo $record->goal_casa . " - ". $record->goal_ospite;?></td>\n <td><?php echo $squadra_ospite->squadra;?></td>\n <td><?php echo $record->goal_casa_1t . " - ". $record->goal_ospite_1t;?></td>\n </tr>\n <?php\n endforeach;\n else: ?>\n <tr>\n <td colspan="6">Non \xc3\xa8 stata trovata nessuna partita!</td>\n </tr>\n <?php endif ?>\n </tbody>\n </table>\n</body>\n</html>\nRun Code Online (Sandbox Code Playgroud)\n我尝试 var_dump() 变量 $squadra_casa 并得到以下结果:
\n\n\n数组(1) {\n[0]=>\n对象(stdClass)#5 (3) {\n["id"]=>\n字符串(2) "18"\n["squadra"]=>\ nstring(6) "富勒姆"\n["campionato"]=>\nstring(1) "1"\n}\n}
\n
但是当我尝试回显 $squadra_casa->squadra 属性时,我收到错误。
\n我该如何解决它?我做错了什么?
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