如何在ListView中显示行号？

Question

显而易见的解决方案是在ModelView元素上使用行号属性,但缺点是在添加记录或更改排序顺序时必须重新生成这些属性.

有优雅的解决方案吗？

Answer 1

我认为你有优雅的解决方案,但这很有效.

XAML:

<ListView Name="listviewNames">
  <ListView.View>
    <GridView>
      <GridView.Columns>
        <GridViewColumn
          Header="Number"
          DisplayMemberBinding="{Binding RelativeSource={RelativeSource FindAncestor, 
                                         AncestorType={x:Type ListViewItem}}, 
                                         Converter={StaticResource IndexConverter}}" />
        <GridViewColumn
          Header="Name"
          DisplayMemberBinding="{Binding Path=Name}" />
      </GridView.Columns>
    </GridView>
  </ListView.View>
</ListView>

ValueConverter:

public class IndexConverter : IValueConverter
{
    public object Convert(object value, Type TargetType, object parameter, CultureInfo culture)
    {
        ListViewItem item = (ListViewItem) value;
        ListView listView = ItemsControl.ItemsControlFromItemContainer(item) as ListView;
        int index = listView.ItemContainerGenerator.IndexFromContainer(item);
        return index.ToString();
    }

    public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

Answer 2

如果您有一个动态列表,其中添加,删除或移动项目,您仍然可以使用这个非常好的解决方案,只需在源列表中的更改完成后让列表视图的当前视图自行刷新.此代码示例直接在数据源列表"mySourceList"(在我的示例中为ObservableCollection)中删除当前项,最后将行号更新为正确的值.

ICollectionView cv = CollectionViewSource.GetDefaultView(listviewNames.ItemsSource);
if (listviewNames.Items.CurrentItem != null)
{
    mySourceList.RemoveAt(cv.CurrentPosition);
    cv.Refresh();
}

Answer 3

首先您需要将设置AlternationCount为items count+1，例如：

<ListView AlternationCount="1000" .... />

然后AlternationIndex将显示真实索引，即使在滚动期间：

 <GridViewColumn
       Header="#" Width="30"
       DisplayMemberBinding="{Binding (ItemsControl.AlternationIndex),
       RelativeSource={RelativeSource AncestorType=ListViewItem}}" />