NSString到NSArray

Question

我想NSString分成一个NSArray.例如,给定:

NSString *myString=@"ABCDEF";

我想要一个NSArray像:

NSArray *myArray={A,B,C,D,E,F};

使用Objective-C和Cocoa如何做到这一点？

Answer 1

NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = @"ABCDEF??";
[letters enumerateSubstringsInRange:NSMakeRange(0, [letters length]) 
                            options:(NSStringEnumerationByComposedCharacterSequences) 
                         usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
    [letterArray addObject:substring];
}];

for (NSString *i in letterArray){
    NSLog(@"%@",i);
}

结果是

A
B
C
D
E
F

??

enumerateSubstringsInRange:options:usingBlock: _{适用于iOS 4+}可以枚举具有不同样式的字符串.一个被称为NSStringEnumerationByComposedCharacterSequences,将逐个列举,但对代理对,基本字符加组合标记,Hangul jamo和印度语辅音簇敏感,所有这些都称为组合字符

请注意,接受的答案 "吞下" and breaks ??闯入?和?.

Answer 2

转变

NSString * string = @"A B C D E F";
NSArray * array = [string componentsSeparatedByString:@" "];
//Notice that in this case I separated the objects by a space because that's the way they are separated in the string

记录

NSLog(@"%@", array);

这是控制台返回的内容

Answer 3

NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
    NSString *ichar  = [NSString stringWithFormat:@"%C", [theString characterAtIndex:i]];
    [chars addObject:ichar];
}