删除重复项而不更改二维列表中的顺序

Question

如何在不更改顺序的情况下删除重复的二维列表？

list_j = [[100,2,3,3], [4,98,99,98], [5,99,98,4], [5,99,98,5], [100,99,98,100,100,6]]

list_pre = [list(set(i)) for i in list_j]
print(list_pre)

[[2, 3, 100], [98, 99, 4], [98, 99, 4, 5], [98, 99, 5], [98, 99, 100, 6]]

如您所见，它更改了顺序。我想要的是[[100,2,3,],...]

期望输出 [[100,2,3,], [4,98,99], [5,99,98,4], [5,99,98], [100,99,98,6]]

Answer 1

使用OrderedDict维护键的插入顺序：

from collections import OrderedDict
list_j = [[100,2,3,3], [4,98,99,98], [5,99,98,4], [5,99,98,5], [100,99,98,100,100,6]]
output = [list(OrderedDict.fromkeys(x)) for x in list_j]

给

[[100, 2, 3], [4, 98, 99], [5, 99, 98, 4], [5, 99, 98], [100, 99, 98, 6]]

如果您使用 Python 3.7 或更高版本，您也可以使用普通字典，因为它们也保持插入顺序：

output = [list(dict.fromkeys(x)) for x in list_j]