Why is the integer not recognized to be more than 0?

Soc*_*nme 0 python python-3.x

Here's something taken out of my code to check if the value is greater than 0 and if it's a number:

while(1):
        n = input("Type a number of rolls to do, to try and get 3 of the same sides in a row.")
        if n.isdigit() and int(n) > 0 == True:
            n = int(n)
            break
        else:
            print("Select a proper integer.")
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For some reason if you enter a value that should stop the loop like 10, it's seen as a wrong integer. Why is that?

che*_*ner 5

Error aside, the "right" way to do this (specifically, without calling int(n) twice), is to simply catch an exception raised by int(n):

while True:
    n = input("Type a number...")
    try:
        n = int(n)
    except ValueError:
        continue

    if n > 0:
        break

    print("Select a positive integer")
    
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