正则表达式中的枚举

Question

我有一个看起来像这样的字符串......

mystring = '{#var#}status has been updated{#var#}with remark{#var#}connect with{#var#}at{#var#}transactions may be{#var#}till{#var#}'

我只需要给它编号，让它看起来像这样......

{#var1#}status has been updated{#var2#}with remark{#var3#}connect with{#var4#}at{#var5#}transactions may be{#var6#}till{#var7#}

这将用数字 1 替换字符串

mystring.replace("{#var#}", "{#var1#}")

不知道如何枚举数字 2,3,4 到 7

Answer 1

mystring = '{#var#}status has been updated{#var#}with remark{#var#}connect with{#var#}at{#var#}transactions may be{#var#}till{#var#}'


for i in range(mystring.count('#var#')):
    mystring = mystring.replace('#var#', f'#var{i + 1}#', 1)

print(mystring)

str.replace接受第三个参数，该参数指定要替换的出现次数，因此此处设置为1。因此，在每次迭代只中第一次出现#var#被替换到f'#var{i + 1}#'那里i从开始0一路攀升到最初出现的次数#var#。