大于目标的最小字母

Question

我写了一个代码，目的是在字母之后返回最小的target字母h，所以在这种情况下，它是i. 但是，下面的代码不会产生输出。有任何想法吗？我感觉问题出在第一个if语句中。

letters = [
    'a',
    'b',
    'c', 'c', 'c', 'c',
    'd',
    'e', 'e', 'e',
    'g',
    'h', 'h', 'h',
    'i',
    'j',
    'k', 'k', 'k',
    'l',
    'm',
    'n',
    'o',
    'p', 'p', 'p',
    'q',
    'r',
    's', 's',
    't'
]

target = 'h'
left = 0
right = len(letters) - 1
mid = left + (right - left) // 2

while left < right:
    if mid == target:
        for i in range(letters[mid], letters[len(letters)]):
            if letters[i] != target:
                print(letters[i])
                break

    if letters[mid] < target:
        left = mid + 1
    elif letters[mid] > target:
        right = mid - 1

Answer 1

letters =     ['a','b','c','c','c','c','d','e','e','e','g','h','h','h','i','j','k','k','k','l','m','n','o','p','p','p','q','r','s','s','t']

target = 'h'

# Find only after target
letters = letters[letters.index(target):]

# Remove target from list
letters = [x for x in letters if x != target]

# Sort list
letters.sort()

# Find char representation of lowest
print(letters[0])