如何在匿名线程中声明异常？

Question

InputStream in = ClientSocket.getInputStream();
new Thread()
{
    public void run() {
        while (true)
        {
            int i = in.read();
            handleInput(i);
        }
    }
}.start();

我正在使用此代码在套接字上侦听新数据并获取:

FaceNetChat.java:37: unreported exception java.io.IOException; must be caught or declared to be thrown
                int i = in.read();
                               ^

当我在" run() " 之后添加" throws IOException "时,我得到:

FaceNetChat.java:34: run() in  cannot implement run() in java.lang.Runnable; overridden method does not throw java.io.IOException
        public void run() throws IOException {
                    ^

这可能很简单,但我很茫然.我怎么通过这个？

Answer 1

您不能覆盖不引发异常的Runnable.run()接口.您必须在run方法中处理异常.

try {
  int i = in.read();
} catch (IOException e) {
  // do something that makes sense for your application
}