可以说我们有以下内容:
create view view_1 as
(
select key, data from some_table_or_view;
);
create table table_1
(
key
more_data
);
create view view_2 as
(
select v1.key, v1.data, t1.more_data
from view_1 v1, table_1 t1
where v1.key = t1.key
);
create table table_2 as
(
key
data
more_data
);
create view view_3 as
(
select key, data, more_data from view_2
union
select key, data, more_data from table_2
);
Run Code Online (Sandbox Code Playgroud)
基本上,我们加入了两个数据源,一个来自连接,一个是原始数据.
我希望能够做到以下几点.
update view_3 set more_data = 'BLAH_MORE_DATA' where key = 'BLAH_KEY';
Run Code Online (Sandbox Code Playgroud)
以某种方式更新table_1或table_2取决于"BLAH_KEY"是否来自table_1或table_2.
目前我能想到的唯一方法是:
create view view_3 as
(
select 'TAB1' as source, key, data, more_data from view_2
union
select 'TAB2' as source, key, data, more_data from table_2
);
Run Code Online (Sandbox Code Playgroud)
然后使用PL/SQL函数进行更新,该函数检查源列并更新相应的表,但这意味着我必须保持视图和PL/SQL函数同步.
我正在寻找一种更好的方法来做到这一点.
您可以在view_3上使用而不是触发器
CREATE OR REPLACE TRIGGER view3_trg
INSTEAD OF UPDATE
ON view_3
FOR EACH ROW
BEGIN
IF :OLD.source = 'TAB1' THEN
UPDATE table_1 t1
set t1.data = :NEW.data
WHERE
t1.key = :OLD.key
;
ELSIF OLD.source = 'TAB2' THEN
UPDATE table_2 t2
set t2.data = :NEW.data
WHERE
t2.key = :OLD.key
;
END IF;
END;
/
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4090 次 |
| 最近记录: |