如何将404错误重定向到ExpressJS中的页面？

Question

我不知道这样做的功能,有人知道吗？

Answer 1

我发现这个例子非常有帮助:

https://github.com/visionmedia/express/blob/master/examples/error-pages/index.js

所以它实际上就是这个部分:

// "app.router" positions our routes
// above the middleware defined below,
// this means that Express will attempt
// to match & call routes _before_ continuing
// on, at which point we assume it's a 404 because
// no route has handled the request.

app.use(app.router);

// Since this is the last non-error-handling
// middleware use()d, we assume 404, as nothing else
// responded.

// $ curl http://localhost:3000/notfound
// $ curl http://localhost:3000/notfound -H "Accept: application/json"
// $ curl http://localhost:3000/notfound -H "Accept: text/plain"

app.use(function(req, res, next){
  res.status(404);

  // respond with html page
  if (req.accepts('html')) {
    res.render('404', { url: req.url });
    return;
  }

  // respond with json
  if (req.accepts('json')) {
    res.send({ error: 'Not found' });
    return;
  }

  // default to plain-text. send()
  res.type('txt').send('Not found');
});

Answer 2

我认为您应首先定义所有路线,并作为最后一条路线添加

//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
  res.status(404).send('what???');
});

一个有效的示例应用程序:

app.js:

var express = require('express'),
    app = express.createServer();

app.use(express.static(__dirname + '/public'));

app.get('/', function(req, res){
  res.send('hello world');
});

//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
  res.send('what???', 404);
});

app.listen(3000, '127.0.0.1');

alfred@alfred-laptop:~/node/stackoverflow/6528876$ mkdir public
alfred@alfred-laptop:~/node/stackoverflow/6528876$ find .
alfred@alfred-laptop:~/node/stackoverflow/6528876$ echo "I don't find a function for that... Anyone knows?" > public/README.txt
alfred@alfred-laptop:~/node/stackoverflow/6528876$ cat public/README.txt 

.
./app.js
./public
./public/README.txt

alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/
hello world
alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/README.txt
I don't find a function for that... Anyone knows?

Answer 3

您可以将中间件放在抛出NotFound错误的最后位置,
甚至可以直接呈现404页面:

app.use(function(req,res){
    res.status(404).render('404.jade');
});

Answer 4

上面的答案是好的,但是其中一半你不会得到404作为你的HTTP状态代码返回,而在另一半,你将无法有自定义模板渲染.在Expressjs中拥有自定义错误页面(404)的最佳方法是

app.use(function(req, res, next){
    res.status(404).render('404_error_template', {title: "Sorry, page not found"});
});

将此代码放在所有URL映射的末尾.

Answer 5

在 app.js 的最后一行，只需要放置这个函数。这将覆盖默认的 page-not-found 错误页面：

app.use(function (req, res) {
    res.status(404).render('error');
});

它将覆盖所有没有有效处理程序的请求并呈现您自己的错误页面。

Answer 6

你的问题的答案是：

app.use(function(req, res) {
    res.status(404).end('error');
});

而且，关于为什么它是最好的方式一个伟大的文章在这里。