如何使用boto和python从存储桶中删除s3版本

Question

当我尝试使用以下行删除存储桶时:

conn = boto.connect_s3(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY)

print conn.delete_Bucket('BucketNameHere').message

它告诉我我试图删除的桶不是空的.

水桶没有钥匙.但它确实有版本.

如何删除版本？

我可以看到使用bucket.list_versions()的版本列表

Java在其s3连接上有一个deleteVersion方法.我在这里找到了代码:

http://bytecoded.blogspot.com/2011/01/recursive-delete-utility-for-version.html

他这行删除版本:

s3.deleteVersion(new DeleteVersionRequest(bucketName, keyName, versionId));

在博托有什么可比性的吗？

Answer 1

Boto确实支持版本1.9c之后的版本化存储桶.以下是它的工作原理:

import boto

s3 = boto.connect_s3()

#Create a versioned bucket
bucket = s3.create_bucket("versioned.example.com")
bucket.configure_versioning(True)

#Create a new key and make a few versions
key = bucket.new_key("versioned_object")
key.set_contents_from_string("Version 1")
key.set_contents_from_string("Version 2")

#Try to delete bucket
bucket.delete()   ## FAILS with 409 Conflict

#Delete our key then try to delete our bucket again
bucket.delete_key("versioned_object")
bucket.delete()   ## STILL FAILS with 409 Conflict

#Let's see what's in there
list(bucket.list())   ## Returns empty list []

#What's in there including versions?
list(bucket.list_versions())   ## Returns list of keys and delete markers

#This time delete all versions including delete markers
for version in bucket.list_versions():
    #NOTE we're still using bucket.delete, we're just adding the version_id parameter
    bucket.delete_key(version.name, version_id = version.version_id)

#Now what's in there
list(bucket.list_versions())   ## Returns empty list []

#Ok, now delete the bucket
bucket.delete()   ## SUCCESS!!