如何改进此邮件地址SQL Server SELECT语句？

Question

如何格式化邮件地址,以便始终将所有非空行推送到顶部？也就是说,我想将地址从下面的结构转换为邮寄地址.

这是结构:

[Line1] [varchar](50) NULL,
[Line2] [varchar](50) NULL,
[Line3] [varchar](50) NULL,
[City] [varchar](50) NULL,
[State] [varchar] (2) NULL,
[PostalCode] [varchar](50) NULL,

以下是一些示例数据:

Line1=
Line2=123 Some Address
Line3=
City=Royal Oak
State=MI
ZIP=45673-2312

以下是结果应该是什么样的(应返回4个不同或单独的字段):

MailAddress1=123 Some Address
MailAddress2=ROYAL OAK MI 45673-2312
MailAddress3=
MailAddress4=

我正在使用SQL Server 2005.

有人在我们公司写了这个逻辑,它似乎很复杂(注意:这不是整个SELECT语句):

,CASE 
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN 
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          ELSE eai.Line3
          END
      ELSE eai.Line2
      END
  ELSE eai.Line1
  END
,CASE 
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN
    CASE 
      WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
      ELSE eai.Line3
      END
  ELSE 
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          ELSE eai.Line3
          END
      ELSE eai.Line2
      END
  END
,CASE
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN NULL
      ELSE
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN NULL
          ELSE ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          END
      END 
  ELSE
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN NULL
          ELSE ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          END
      ELSE 
          CASE 
            WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
            ELSE eai.Line3
            END
      END
  END
,CASE WHEN eai.Line2 IS NOT NULL AND eai.Line2 <> '' AND eai.Line3 IS NOT NULL AND eai.Line3 <> '' THEN eai.City + ' ' + eai.RegionCode + '  ' + eai.PostalCode ELSE NULL END

Answer 1

这样做的方法是使用UNPIVOT.这是解决方案:

With AddrTable as (
Select AddrFld, MailAddr From (
Select Cast(ISNULL([Line1], '') as Varchar(102)) as [A1], 
       Cast(ISNULL([Line2], '') as Varchar(102)) as [A2], 
       Cast(ISNULL([Line3], '') as Varchar(102)) as [A3], 
       Cast(ISNULL(LTRIM(RTRIM(City)),'') + ' ' + ISNULL(LTRIM(RTRIM(RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(PostalCode)),'') as Varchar(102)) as A4
From TableName Where UniqueID=@UniqueID) p
Unpivot (MailAddr For AddrFld in ([A1], [A2], [A3], [A4])) as unpvt)
Select Row_Number() over (Order by (Case Len(MailAddr) When 0 then 1 else 0 end), AddrFld) as RN, 
MailAddr From AddrTable 
Order By RN

这是输出:

Address1
Westby WI  55555
-empty line-
-empty line-

请注意,我必须使用"Varchar(102)"作为字段长度(unpivot要求所有字段都相同),因为您的城市/地区/邮政总共最多可以有102个字符.另请注意,"@ UniqueID"是您需要的记录的标识符.这将返回四行,总是四行,其中包含您的地址所需的数据.

更新:如果您需要将其作为一组四列而不是四行返回,则只需将其放入视图中,然后使用 Pivot查询视图.我在这里包含了视图的完整性,因为我必须在创建视图时稍微改变上面的内容,因此包含了uniqueID字段并且没有进行排序(排序现在在查询中完成):

Create View AddressRows AS
 With AddrTable as (
 Select UniqueID, AddrFld, MailAddr From (
 Select UniqueID, 
       Cast(ISNULL([Line1], '') as Varchar(102)) as [A1], 
       Cast(ISNULL([Line2], '') as Varchar(102)) as [A2], 
       Cast(ISNULL([Line3], '') as Varchar(102)) as [A3], 
       Cast(ISNULL(LTRIM(RTRIM(City)),'') + ' ' + ISNULL(LTRIM(RTRIM(RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(PostalCode)),'') as Varchar(102)) as A4
 From TableName Where UniqueID=@UniqueID) p
 Unpivot (MailAddr For AddrFld in ([A1], [A2], [A3], [A4])) as unpvt)
 Select UniqueID, 
       Row_Number() over (Order by (Case Len(MailAddr) When 0 then 1 else 0 end), AddrFld) as RN, 
       MailAddr From AddrTable 

然后,当你想拉出匹配的"行"时,使用这个SQL将其转回(注意我使用UniqueID再次查询):

Select [Addr1], [Addr2], [Addr3], [Addr4] From (
Select Top 4 'Addr' + Cast(Row_Number() over (Order by RN) as Varchar(12)) as AddrCol,  -- "Top 4" needed so we can sneak the "Order By" in 
MailAddr 
From AddressRows Where UniqueID=@UniqueID
) p PIVOT (Max([MailAddr]) for AddrCol in ([Addr1], [Addr2], [Addr3], [Addr4])
) as pvt

返回:

Addr1            Addr2                Addr3           Addr4
--------------   ------------------   -------------   ------------------ 
Address1         Westby WI  54667