jquery找到元素

use*_*507 0 jquery

为了在我点击的链接中找到类"imgBtn"(类 - "checkVacancy a"),我需要什么选择器?

      <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302a"></div>
  </div>
  <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302b"></div>
  </div>
  <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302c"></div>
  </div>
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这是我使用的JS

   $(function(){
        $('.checkVacancy a').click(function() {

          //access only child image
          $('.imgBtn').attr('src','http://www.ajaxload.info/cache/9D/E5/1C/00/00/00/1-0.gif');                  

        });
    });
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示例jsbin

Joh*_*hnP 5

你想要的是什么

var imgBtn = $(this).find('.imgBtn');
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这将在您单击的链接中找到该图像.