我有以下列表:
[('mail', 167, datetime.datetime(2010, 9, 29)) ,
('name', 1317, datetime.datetime(2011, 12, 12)),
('mail', 1045, datetime.datetime(2010, 8, 13)),
('name', 3, datetime.datetime(2011, 11, 3))]
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并且我想从列表中删除项目,其中元组中的第一项是重合的,其中日期不是最新的.换句话说,我需要得到这个:
[('mail', 167, datetime.datetime(2010, 9, 29)) ,
('name', 1317, datetime.datetime(2011, 12, 12))]
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Bjö*_*lex 15
到目前为止,您可以使用字典存储给定键的最高值:
temp = {}
for key, number, date in input_list:
if key not in temp: # we see this key for the first time
temp[key] = (key, number, date)
else:
if temp[key][2] < date: # the new date is larger than the old one
temp[key] = (key, number, date)
result = temp.values()
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