在sqlite中是否允许自引用或递归外键?有没有特殊的语法来实现这一目标?到目前为止,我尝试了以下无济于事:FOREIGN KEY(ParentPrimaryKeyId) REFERENCES ThisTableName(PrimaryKeyId)
作为参考,我的目标是iOS 4中的sqlite 3.6.22.
小智 9
是的sqlite支持自引用外键,例如:
sqlite> PRAGMA foreign_keys = ON;
sqlite> CREATE TABLE SomeTable (
...> id INTEGER PRIMARY KEY AUTOINCREMENT,
...> parent_id INTEGER,
...> FOREIGN KEY(parent_id) REFERENCES SomeTable(id));
sqlite> INSERT INTO SomeTable (parent_id) VALUES (234324);
Error: foreign key constraint failed
sqlite> INSERT INTO SomeTable (parent_id) VALUES (NULL);
sqlite> SELECT * FROM SomeTable;
1|
sqlite> INSERT INTO SomeTable (parent_id) VALUES (1);
sqlite> SELECT * FROM SomeTable;
1|
2|1
sqlite>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4001 次 |
| 最近记录: |