将Hex的字符串转换为文本的NSString？

Question

我需要将十六进制值的NSString转换为文本的NSString(ASCII).例如,我需要这样的东西:

"68 65 78 61 64 65 63 69 6d 61 6c" to be "hexadecimal"

我已经查看并调整了此线程中的代码,但它对我不起作用.它仅适用于一对十六进制.与空间有关？任何提示或示例代码都非常感谢.

Answer 1

那么我会为你的目的修改同样的东西.

NSString * str = @"68 65 78 61 64 65 63 69 6d 61 6c";
NSMutableString * newString = [NSMutableString string];

NSArray * components = [str componentsSeparatedByString:@" "];
for ( NSString * component in components ) {
    int value = 0;
    sscanf([component cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value);
    [newString appendFormat:@"%c", (char)value];
}

NSLog(@"%@", newString);

Answer 2

您可以使用NSScanner获取每个角色.需要空格来分隔每个值,否则扫描仪将继续扫描并忽略其他数据.

- (NSString *)hexToString:(NSString *)string {
    NSMutableString * newString = [[NSMutableString alloc] init];
    NSScanner *scanner = [[NSScanner alloc] initWithString:string];
    unsigned value;
    while([scanner scanHexInt:&value]) {
        [newString appendFormat:@"%c",(char)(value & 0xFF)];
    }
    string = [newString copy];
    [newString release];
    return [string autorelease];
}

// called like:
NSLog(@"%@",[self hexToString:@"68 65 78 61 64 65 63 69 6d 61 6c"]);