Spring Data @Query + 规范

Question

你能帮我连接规范和查询吗？分页工作完美，但我对规范有问题，没有在其中添加搜索参数。

public interface RakebackRepository extends JpaRepository<Rakeback, Long>,JpaSpecificationExecutor<Rakeback> {

    @Override    
    @Query(value = "SELECT new domain.model.poker.rakeback.Rakeback(ppr.playerId, SUM(ppr.rakeSum), SUM(ppr.fullRakeBackSum), max(ppra.rakeBackBalance), max(ppra.rakebackRank)) FROM Rakeback as ppr LEFT JOIN ppr.Rakeback as ppra on ppra.status = 'active' LEFT JOIN ppra.rakebackRank as rbb on ppra.rakeBackRankId = rbb.id GROUP BY ppr.playerId ")   
    Page<Rakeback> findAll(Specification<Rakeback> specification, Pageable pageable);
    
    }

这是来自日志的 SQL

select pokerplaye0_.player_id as col_0_0_,  sum(pokerplaye0_.rake_sum) as col_1_0_,  sum(pokerplaye0_.full_rake_back_sum) as col_2_0_,  max(pokerplaye1_.rake_back_balance) as col_3_0_,  max(pokerplaye1_.rake_back_rank_id) as col_4_0_ 
from rakeback.players_rakebacks pokerplaye0_  
left outer join rakeback.players_rakebacks pokerplaye1_ on pokerplaye0_.player_id=pokerplaye1_.player_id and (pokerplaye1_.status='active')  
left outer join rakeback.rakeback_settings pokerrakeb2_ on pokerplaye1_.rake_back_rank_id=pokerrakeb2_.id and (pokerplaye1_.rake_back_rank_id=pokerrakeb2_.id) 
group by pokerplaye0_.player_id 
order by pokerplaye0_.player_id desc limit ?

这是我的演讲

public class RakebackListSpec {

private final OperatorService operatorService;
private final PlayerService playerService;



public static Specification<Rakeback> byPlayerId(Long id) {
    return (root, query, criteriaBuilder) ->
            criteriaBuilder.equal(root.get("playerId"), id);
}

public static Specification<Rakeback> byOperator(Integer operatorId) {
    return (root, query, criteriaBuilder) ->
            criteriaBuilder.equal(root.get("operatorId"), operatorId);
}

public Specification<Rakeback> getSpec(RakebackListRequestDto request) {

    Specification<Rakeback> spec = Specification.where(byOperator(operatorService.getOperator().getId()));

    if(request.getOpPlayerId() != null){
        CorePlayer player = playerService.getPlayerByOpPlayerId(request.getOpPlayerId());
        spec = spec.and(byPlayerId(player.getId()));
    }


    return spec;
}

Answer 1

@Query并且Specification不能合并。有关详细信息，请参阅此 SO 问题/答案。