Ser*_*dez 2 json backend mongodb express typescript
我正在使用 ExpressJS 和 Mongo 处理 REST api,并且我有一个包含 N 个级别的集合。
所以为了解决这个问题,我在 mongo 中使用了一个递归表(或集合),其中一个字段是 id,每个寄存器都有一个 parent_id,它与它的孩子处于同一级别。为了更好地解释这一点,这里是一个 ER 表示
因此,正如您所见,mongo 会像这样保存数据 json(帐户级别 0 的父级为 null)
[
{ "id": "45TYYU", "parent_id": null, "name":"account 1", "type": 1, "category": 1 },
{ "id": "45TYYXT", "parent_id": "45TYYU", "name":"account 2", "type": 1, "category": 1 },
{ "id": "45TYYPZ", "parent_id": "45TYYU", "name":"account 3", "type": 1, "category": 1 },
{ "id": "45TYYPZRE", "parent_id": "45TYYPZ", "name":"account 4", "type": 1, "category": 1 },
{ "id": "45TYYPZSX", "parent_id": "45TYYPZ", "name":"account 5", "type": 1, "category": 1 },
{ "id": "45TYYPZGP", "parent_id": "45TYYXT", "name":"account 6", "type": 1, "category": 1 }
]
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账户 2 和账户 3 是账户 1 的孩子,而账户 4 和账户 5 是账户树的孩子,账户 6 是账户 2 的孩子……但每个寄存器都处于同一逻辑级别,仅通过 parent_id 进行标识。
所以我需要将这些数据转换为 GET 方法来重构它,如下所示:
[
{
"id": "45TYYU",
"parent_id": null,
"name":"account 1",
"type": 1,
"category": 1,
"children": [
{
"id": "45TYYXT",
"parent_id": "45TYYU",
"name":"account 2",
"type": 1,
"category": 1,
"children": [
{ "id": "45TYYPZGP", "parent_id": "45TYYXT", "name":"account 6", "type": 1, "category": 1 }
]
},
{
"id": "45TYYPZ",
"parent_id": "45TYYU",
"name":"account 3",
"type": 1,
"category": 1,
"children": [
{ "id": "45TYYPZRE", "parent_id": "45TYYPZ", "name":"account 4", "type": 1, "category": 1 },
{ "id": "45TYYPZSX", "parent_id": "45TYYPZ", "name":"account 5", "type": 1, "category": 1 }
]
}
]
},
{
"id": "45TFJK",
"parent_id": null,
"name":"account 7",
"type": 1,
"category": 1,
"children": [
{
"id": "47HJJT",
"parent_id": "45TFJK",
"name":"account 8",
"type": 1,
"category": 1
},
{
"id": "47YHJU",
"parent_id": "45TFJK",
"name":"account 8",
"type": 1,
"category": 1
}
]
}
]
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是的...父母级别 0 的 parent_id 为空,我想将它的孩子放在一个名为“children”的数组中,然后在 GET 响应中像这样发送到我的 UI
在 expressJS 中执行此操作的最佳方法是什么?是否有允许我这样做的库或组件?
谢谢
您可以使用$graphLookup和其他有用的数组运算符,
$match记录只有的过滤器parent_id是null$graphLookup 在depthField中获取子记录和深度数 level$unwind解构children数组并允许不删除空子项$sort按深度字段level降序排列$group按id字段并重建children数组db.collection.aggregate([
{ $match: { parent_id: null } },
{
$graphLookup: {
from: "collection",
startWith: "$id",
connectFromField: "id",
connectToField: "parent_id",
depthField: "level",
as: "children"
}
},
{
$unwind: {
path: "$children",
preserveNullAndEmptyArrays: true
}
},
{ $sort: { "children.level": -1 } },
{
$group: {
_id: "$id",
parent_id: { $first: "$parent_id" },
name: { $first: "$name" },
type: { $first: "$type" },
category: { $first: 1 },
children: { $push: "$children" }
}
},
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$addFields 现在找到嵌套级别的孩子并分配给它的级别,
children数组循环。level默认值为-1,presentChild为[],prevChild为条件目的为[]$let 初始化字段:
prev根据条件如果两者level相等则返回prevChild否则返回presentChildcurrent根据条件,如果两者level相等则返回,presentChild否则返回[]in从初始化字段返回level字段和prevChild字段
presentChild $filter children从prev数组并返回,将当前对象与children数组 using合并,$mergeObjects并与currentlet 数组连接 using$concatArrays$addFields只返回presentChild数组,因为我们只需要处理过的数组 {
$addFields: {
children: {
$reduce: {
input: "$children",
initialValue: { level: -1, presentChild: [], prevChild: [] },
in: {
$let: {
vars: {
prev: {
$cond: [
{ $eq: ["$$value.level", "$$this.level"] },
"$$value.prevChild",
"$$value.presentChild"
]
},
current: {
$cond: [{ $eq: ["$$value.level", "$$this.level"] }, "$$value.presentChild", []]
}
},
in: {
level: "$$this.level",
prevChild: "$$prev",
presentChild: {
$concatArrays: [
"$$current",
[
{
$mergeObjects: [
"$$this",
{
children: {
$filter: {
input: "$$prev",
as: "e",
cond: { $eq: ["$$e.parent_id", "$$this.id"] }
}
}
}
]
}
]
]
}
}
}
}
}
}
}
},
{
$addFields: {
id: "$_id",
children: "$children.presentChild"
}
}
])
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