kam*_*hit 6 oracle geometry oracle-spatial
我需要通过 Pl SQL Query 计算两个位置之间的距离。我试过一些 Qry 但没有得到它。
为此,我们在 SQL 中使用 Query 如下
SELECT ROUND(geography::Point(cast('19.2806118' as float),cast('72.8757395' as float) ,
4326).STDistance(geography::Point(cast('19.4482006' as float),
cast('72.7912511' as float), 4326))/1000,1) DIST
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结果:20.6
为了在 ORACLE Db 中计算相同的值,我在互联网上找到了一个解决方案,如下所示
select sdo_geom.sdo_distance(sdo_geometry(2001,4326,null,sdo_elem_info_array(1, 1, 1),
sdo_ordinate_array( 19.2806118,72.8757395)),sdo_geometry(2001,4326, null,sdo_elem_info_array(1, 1,
1),sdo_ordinate_array( 19.4482006,72.7912511)),1,'unit=KM') distance_km from dual
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结果:10.9271..
请建议在我获得 MS SQL 时会给我结果的方法
当我获取 MS SQL 时,请建议在 KM 中给出结果的方法
将参数顺序交换19.2806118,72.8757395为72.8757395,19.2806118
select sdo_geom.sdo_distance(
sdo_geometry(2001,4326,null,sdo_elem_info_array(1, 1, 1),
sdo_ordinate_array(72.8757395,19.2806118)),
sdo_geometry(2001,4326, null,sdo_elem_info_array(1, 1,1),
sdo_ordinate_array(72.7912511,19.4482006))
,1
,'unit=KM') distance_km
from dual;
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产生与 SQL Server 完全相同的结果:20.5657053685075
db<>fiddle 演示 Oracle
db<>fiddle 演示 SQL Server
或者通过使用sdo_point:
SELECT sdo_geom.sdo_distance(
sdo_geometry(2001, 4326,
sdo_point_type(72.8757395, 19.2806118, NULL), NULL, NULL),
sdo_geometry(2001, 4326,
sdo_point_type(72.7912511, 19.4482006, NULL), NULL, NULL),
1, 'unit=KM') distance_in_m
from DUAL;
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SQL服务器:geography::Point ( Lat, Long, SRID )