oracle DB中具有纬度和经度的两点之间的距离

kam*_*hit 6 oracle geometry oracle-spatial

我需要通过 Pl SQL Query 计算两个位置之间的距离。我试过一些 Qry 但没有得到它。

为此,我们在 SQL 中使用 Query 如下

SELECT ROUND(geography::Point(cast('19.2806118' as float),cast('72.8757395' as float) , 
4326).STDistance(geography::Point(cast('19.4482006' as float),
cast('72.7912511' as float), 4326))/1000,1) DIST
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结果:20.6

为了在 ORACLE Db 中计算相同的值,我在互联网上找到了一个解决方案,如下所示

select sdo_geom.sdo_distance(sdo_geometry(2001,4326,null,sdo_elem_info_array(1, 1, 1),
sdo_ordinate_array( 19.2806118,72.8757395)),sdo_geometry(2001,4326, null,sdo_elem_info_array(1, 1, 
1),sdo_ordinate_array( 19.4482006,72.7912511)),1,'unit=KM') distance_km from dual
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结果:10.9271..

请建议在我获得 MS SQL 时会给我结果的方法

Luk*_*zda 5

当我获取 MS SQL 时,请建议在 KM 中给出结果的方法

将参数顺序交换19.2806118,72.875739572.8757395,19.2806118

select sdo_geom.sdo_distance(
   sdo_geometry(2001,4326,null,sdo_elem_info_array(1, 1, 1),
                 sdo_ordinate_array(72.8757395,19.2806118)),
   sdo_geometry(2001,4326, null,sdo_elem_info_array(1, 1,1),
                 sdo_ordinate_array(72.7912511,19.4482006))
   ,1
   ,'unit=KM') distance_km 
from dual;
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产生与 SQL Server 完全相同的结果:20.5657053685075

db<>fiddle 演示 Oracle
db<>fiddle 演示 SQL Server

或者通过使用sdo_point

SELECT sdo_geom.sdo_distance(
         sdo_geometry(2001, 4326,
                sdo_point_type(72.8757395, 19.2806118, NULL), NULL, NULL),
          sdo_geometry(2001, 4326,
               sdo_point_type(72.7912511, 19.4482006, NULL), NULL, NULL),
               1, 'unit=KM') distance_in_m
from DUAL;
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SQL服务器:geography::Point ( Lat, Long, SRID )