PHP
<?php
$url = 'http://vimeo.com/25451551';
/* http://www.vimeo.com/25451551 ... www.vimeo.com/25451551 */
$url = preg_match('???', $url);
echo $url;
?>
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25451551
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任何帮助都将不胜感激.谢谢.
Tim*_*per 16
如果允许视频ID以0开头,则可能需要稍微调整以下代码:
$url = 'http://vimeo.com/25451551';
sscanf(parse_url($url, PHP_URL_PATH), '/%d', $video_id);
// $video_id = int(25451551)
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$url = 'http://vimeo.com/25451551/test';
$result = preg_match('/(\d+)/', $url, $matches);
if ($result) {
var_dump($matches[0]);
}
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