And*_*rew 5 arrays fortran dimensions
是否有必要在任何其他代码之前声明数组维度?例如,我编写了以下简化示例代码:
PROGRAM mytest
IMPLICIT NONE
INTEGER :: i, j, k, mysum
! Let array c be a k-by-k**2 array
! Determine k within the program by some means...for example,
mysum=0
DO i=1, 3
mysum=mysum+1
END DO
k=mysum
REAL, DIMENSION(k, k**2) :: c
WRITE(*,*) "k=", k
WRITE(*,*) "k**2=", k**2
WRITE(*,*)
DO i=1,size(c,1)
WRITE(*,"(100(3X,F3.1))") (c(i,j), j=1,size(c,2))
END DO
END PROGRAM mytest
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我试图做的一点是,我想创建一个数组c是k-by- k**2大小,并且k仅由代码中的其他计算确定; k一开始就不知道.
但是,上面的代码在编译时给出了以下错误消息:
mytest.f90:13.31:
REAL, DIMENSION(k, k**2) :: c
1
Error: Unexpected data declaration statement at (1)
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我的代码中的第13行是我最终声明的行c:REAL, DIMENSION(k, k**2) :: c.
另一方面,如果我改为声明k并预先指定其尺寸,
PROGRAM mytest
IMPLICIT NONE
INTEGER :: i, j, k, mysum
REAL, DIMENSION(3,9) :: c
! Let array c be a k-by-k**2 array
! Determine k within the program by some means...for example,
mysum=0
DO i=1, 3
mysum=mysum+1
END DO
k=mysum
WRITE(*,*) "k=", k
WRITE(*,*) "k**2=", k**2
WRITE(*,*)
DO i=1,size(c,1)
WRITE(*,"(100(3X,F3.1))") (c(i,j), j=1,size(c,2))
END DO
END PROGRAM mytest
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我得到了正确的输出:
k= 3
k**2= 9
0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0
0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0
0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0
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但是,由于我k事先并不知道,我不能在我的实际代码中做到这一点.有没有办法在c最初"声明"数组而不指定其尺寸,然后在k知道值后指定尺寸?
Jon*_*rsi 11
您想使用可分配的数组:
PROGRAM mytest
IMPLICIT NONE
INTEGER :: i, j, k, mysum
REAL, DIMENSION(:,:), allocatable :: c !<- c is allocatable, rank 2
! Let array c be a k-by-k**2 array
! Determine k within the program by some means...for example,
mysum=0
DO i=1, 3
mysum=mysum+1
END DO
k=mysum
WRITE(*,*) "k=", k
WRITE(*,*) "k**2=", k**2
WRITE(*,*)
allocate(c(k,k**2)) ! <-- allocate array c with supplied shape
DO i=1,size(c,1)
WRITE(*,"(100(3X,F3.1))") (c(i,j), j=1,size(c,2))
END DO
deallocate(c) ! <-- deallocate when done
END PROGRAM mytest
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