Sha*_*ker 5 python datetime python-datetime pandas
我正在尝试使用以下函数获取两个日期之间的天数
df['date'] = pd.to_datetime(df.date)
# Creating a function that returns the number of days
def calculate_days(date):
today = pd.Timestamp('today')
return today - date
# Apply the function to the column date
df['days'] = df['date'].apply(lambda x: calculate_days(x))
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结果看起来像这样
153 天 10:16:46.294037
但我想让它说153。我该如何处理这个问题?
为了提高性能,您可以在不使用 for 的情况下减去值,apply避免循环使用Series.rsubfor 从右侧减去:
df['date'] = pd.to_datetime(df.date)
df['days'] = df['date'].rsub(pd.Timestamp('today')).dt.days
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工作原理如下:
df['days'] = (pd.Timestamp('today') - df['date']).dt.days
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如果想使用您的解决方案:
df['date'] = pd.to_datetime(df.date)
def calculate_days(date):
today = pd.Timestamp('today')
return (today - date).days
df['days'] = df['date'].apply(lambda x: calculate_days(x))
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或者:
df['date'] = pd.to_datetime(df.date)
def calculate_days(date):
today = pd.Timestamp('today')
return (today - date)
df['days'] = df['date'].apply(lambda x: calculate_days(x)).dt.days
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