如何有效地选择所有重复项

Question

我想选择具有表中已存在的值的所有行.我找不到更好的解决方案

select * 
from provisioning_requests tt 
where code in (select code 
               from provisioning_requests tt2 
               where tt2.id <> tt.id)

这似乎有点幼稚.有人有更好的解决方案吗？

Answer 1

select * 
from provisioning_requests t1
 join (select code from provisioning_requests group by code having count(*)>1) t2
 ON t1.code = t2.code

要么

select * 
from provisioning_requests
 WHERE code in (select code from provisioning_requests group by code having count(*)>1)

Answer 2

自动加入完成工作

select tt.* 
from provisioning_requests tt 
    INNER JOIN provisioning_requests tt2 
        ON tt.code = tt2.code
        AND tt2.id <> tt.id