将对象序列化为具有属性和子元素的元素

Question

我希望使用System.Xml.Serialization.XmlSerializer定义将生成以下xml的类.我正在努力获取项目列表,其中的属性不包含'item'元素的子'container'元素.

<?xml version="1.0" ?>
<myroot>
   <items attr1="hello" attr2="world">
      <item id="1" />
      <item id="2" />
      <item id="3" />
   </items>
</myroot>

Answer 1

有XmlSerializer事情或者列表或他们的成员.要做到这一点,你需要:

[XmlRoot("myroot")]
public class MyRoot {
    [XmlElement("items")]
    public MyListWrapper Items {get;set;}
}

public class MyListWrapper {
    [XmlAttribute("attr1")]
    public string Attribute1 {get;set;}
    [XmlAttribute("attr2")]
    public string Attribute2 {get;set;}
    [XmlElement("item")]
    public List<MyItem> Items {get;set;}
}
public class MyItem {
    [XmlAttribute("id")]
    public int Id {get;set;}
}

用例子:

var ser = new XmlSerializer(typeof(MyRoot));
var obj = new MyRoot
{
    Items = new MyListWrapper
    {
        Attribute1 = "hello",
        Attribute2 = "world",
        Items = new List<MyItem>
        {
            new MyItem { Id = 1},
            new MyItem { Id = 2},
            new MyItem { Id = 3}
        }
    }
};
ser.Serialize(Console.Out, obj);

产生:

<myroot xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://
www.w3.org/2001/XMLSchema">
  <items attr1="hello" attr2="world">
    <item id="1" />
    <item id="2" />
    <item id="3" />
  </items>
</myroot>

当然,如果需要,可以删除xsi/ xsdnamespace别名.