我不明白这里有什么问题,但我可能会误解语法.我正在尝试从我的"用户"mnesia表中删除一个名为"ryan"的"用户"记录(其中有多个).这是我做的:
Delete=#user{first_name = "ryan", _ = '_'},
mnesia:dirty_delete_object(Delete)
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这是我的记录定义:
-record(user, {id,
username,
password,
email,
first_name,
last_name,
last_login, % Date/time user last logged in
reg_date}). % Date/time user registered the account
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这是我得到的例外:
** exception exit: {aborted,
{bad_type,user,
{user,'_','_','_','_',"ryan",'_','_','_'}}}
in function mnesia:abort/1
in call from users:register/1
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这似乎是一场完美的比赛.什么可能导致这个问题?
gle*_*ber 12
mnesia:delete_object/1并/3用于从表中删除给定的记录.它不会根据匹配规范删除多个记录.它只是一个更精确的版本mnesia:delete/*- 它为您提供了一种从包表中删除特定记录的方法.
要删除多个匹配规范的记录(例如,使用name="ryan"),请使用以下代码:
Delete=#user{first_name = "ryan", _ = '_'},
List = mnesia:dirty_match_object(Delete)
lists:foreach(fun(X) ->
mnesia:dirty_delete_object(X)
end, List).
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或者是它的交易版本:
Delete=#user{first_name = "ryan", _ = '_'},
Fun = fun() ->
List = mnesia:match_object(Delete)
lists:foreach(fun(X) ->
mnesia:delete_object(X)
end, List)
end,
mnesia:transaction(Fun).
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