如何使用正则表达式拆分字符串而不消耗拆分器部分？

Question

如何在不消耗拆分器部分的情况下拆分字符串？
像这样的东西，但:我使用的是#[a-fA-F0-9]{6}正则表达式。

String from = "one:two:three";
String[] to  = ["one",":","two",":","three"];

我已经尝试过使用 commons lib，因为它有，StringUtils.splitPreserveAllTokens()但它不适用于正则表达式。

编辑：我想我应该更具体，但这更多是我正在寻找的。

String string = "Some text here #58a337test #a5fadbtest #123456test as well.
 #58a337Word#a5fadbwith#123456more hex codes.";

String[] parts = string.split("#[a-fA-F0-9]{6}");
/*Output: ["Some text here ","#58a337","test ","#a5fadb","test ","#123456","test as well. ",
"#58a337","Word","#a5fadb","with","#123456","more hex codes."]*/

编辑2：解决方案！

final String string = "Some text here #58a337test #a5fadbtest #123456test as
 well. #58a337Word#a5fadbwith#123456more hex codes.";

String[] parts = string.split("(?=#.{6})|(?<=#.{6})");
for(String s: parts) {
    System.out.println(s);
}

输出：

Some text here 
#58a337
test 
#a5fadb
test 
#123456
test as well. 
#58a337
Word
#a5fadb
with
#123456
more hex codes.

Answer 1

您可以使用\\b(word-break, \escaped) 在您的情况下拆分，

final String string = "one:two:three";
    
String[] parts = string.split("\\b");
for(String s: parts) {
    System.out.println(s);
}

在线试试吧！