如何用条形图绘制最小/最大条形

Vin*_*ent 4 python matplotlib pandas seaborn

我想调整我的绘图代码以显示最小/最大条形,如下图所示:

我的代码是:

from datetime import datetime, timedelta
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
sns.set_style("white")
sns.set_style('darkgrid',{"axes.facecolor": ".92"}) # (1)
sns.set_context('notebook')

Delay = ['S1', 'S2', 'S3', 'S4']

Time = [87, 66, 90, 55]

df = pd.DataFrame({'Delay':Delay,'Time':Time})
print("Accuracy")

display(df) # in jupyter

fig, ax = plt.subplots(figsize = (8,6))

x = Delay
y = Time

plt.xlabel("Delay", size=14)
plt.ylim(-0.3, 100)
width = 0.1

for i, j in zip(x,y): 
    ax.bar(i,j, edgecolor = "black",
        error_kw=dict(lw=1, capsize=1, capthick=1))  
    ax.set(ylabel = 'Accuracy')

from matplotlib import ticker
ax.yaxis.set_major_locator(ticker.MultipleLocator(10)) 
plt.savefig("Try.png", dpi=300, bbox_inches='tight')
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代码产生这个图:

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我想添加的最小/最大是:

87 (60-90)
66 (40-70)
90 (80-93)
55 (23-60)
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预先感谢您的帮助。

Tre*_*ney 7

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns

# set edgecolor param (this is a global setting, so only set it once)
plt.rcParams["patch.force_edgecolor"] = True

# setup the dataframe
Delay = ['S1', 'S2', 'S3', 'S4']

Time = [87, 66, 90, 55]

df = pd.DataFrame({'Delay':Delay,'Time':Time})

# create a dict for the errors
error = {87: {'max': 90,'min': 60}, 66: {'max': 70,'min': 40}, 90: {'max': 93,'min': 80}, 55: {'max': 60,'min': 23}}
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seaborn.barplot

  • seaborn.barplot将自动添加误差线,如链接中的示例所示。然而,这是特定于使用许多数据点的。在这种情况下,一个值被指定为错误,但错误不是从数据中确定的。
    • 通过这种方式添加误差线时,capsize可以指定该参数,在误差线的顶部和底部添加水平线。
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns

# set edgecolor param (this is a global setting, so only set it once)
plt.rcParams["patch.force_edgecolor"] = True

# setup the dataframe
Delay = ['S1', 'S2', 'S3', 'S4']

Time = [87, 66, 90, 55]

df = pd.DataFrame({'Delay':Delay,'Time':Time})

# create a dict for the errors
error = {87: {'max': 90,'min': 60}, 66: {'max': 70,'min': 40}, 90: {'max': 93,'min': 80}, 55: {'max': 60,'min': 23}}
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  • 正如gepcel答案中所述,该参数可用于显式向 API 提供错误。 yerr
    • 但是,您的错误格式对于参数来说不正确。yerr期望值与条形顶部相关
      • S1是 87,min是 60,max是 90。 因此,ymin是 27, (87-60),ymax是 3, (90-87)。
  • seaborn.barplot capsize参数似乎不适用于yerr,因此您必须设置matplotlib 'errorbar.capsize' rcParmas。请参阅Matplotlib 错误栏上限缺失
# plot the figure
fig, ax = plt.subplots(figsize=(8, 6))
sns.barplot(x='Delay', y='Time', data=df, ax=ax)

# add the lines for the errors 
for p in ax.patches:
    x = p.get_x()  # get the bottom left x corner of the bar
    w = p.get_width()  # get width of bar
    h = p.get_height()  # get height of bar
    min_y = error[h]['min']  # use h to get min from dict z
    max_y = error[h]['max']  # use h to get max from dict z
    plt.vlines(x+w/2, min_y, max_y, color='k')  # draw a vertical line
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pandas.DataFrame.plot.bar

# set capsize param (this is a global setting, so only set it once)
plt.rcParams['errorbar.capsize'] = 10

# create dataframe as shown by gepcel
Delay = ['S1', 'S2', 'S3', 'S4']

Time = [87, 66, 90, 55]
_min = [60, 40, 80, 23]
_max = [90, 70, 93, 60]
df = pd.DataFrame({'Delay':Delay,'Time':Time, 'Min': _min, 'Max': _max})

# create ymin and ymax
df['ymin'] = df.Time - df.Min
df['ymax'] = df.Max - df.Time

# extract ymin and ymax into a (2, N) array as required by the yerr parameter
yerr = df[['ymin', 'ymax']].T.to_numpy()

# plot with error bars
fig, ax = plt.subplots(figsize=(8, 6))
sns.barplot(x='Delay', y='Time', data=df, yerr=yerr, ax=ax)
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ax.bar

fig, ax = plt.subplots(figsize=(8, 6))

df.plot.bar(x='Delay', y='Time', ax=ax)

for p in ax.patches:
    x = p.get_x()  # get the bottom left x corner of the bar
    w = p.get_width()  # get width of bar
    h = p.get_height()  # get height of bar
    min_y = error[h]['min']  # use h to get min from dict z
    max_y = error[h]['max']  # use h to get max from dict z
    plt.vlines(x+w/2, min_y, max_y, color='k')  # draw a vertical line
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在此输入图像描述