"ORA-01008:并非所有变量都绑定"错误

Question

我使用以下方法通过使用jdbc计算工资单,但"ORA-01008:并非所有变量绑定"错误都没有删除.

有什么好主意吗？

我正在使用以下代码

public double getPayroll(){
            ResultSet rs = null;
            ResultSet rs1 = null;
            ResultSet rs2 = null;

            Connection conn = null;
            PreparedStatement pstmt = null;
            try {
                    conn = getDBConnection();
                    double dailyPay=0,basicPay=0,payroll2=0;
                    int houseRent=0,convAllow=0,noOfPresents=0,empId=0;
                    String q = "select e_id from employee";
                    pstmt = conn.prepareStatement(q);
                    rs = pstmt.executeQuery();
                    while (rs.next()) {
                        empId=rs.getInt(1);
                        String q1 = "select count(att_status) from attendance where att_status='p'";
                        pstmt = conn.prepareStatement(q1);
                        rs1 = pstmt.executeQuery(q1);
                        while(rs1.next()){
                            noOfPresents=rs1.getInt(1);
                            String q2 = "select e_salary,e_house_rent,e_conv_allow from employee where e_id=?";
                            pstmt = conn.prepareStatement(q2);
                            pstmt.setInt(1,empId);
                            rs2 = pstmt.executeQuery(q2);
                            while(rs2.next()){
                                dailyPay=rs2.getInt(1)/22;
                                houseRent=rs2.getInt(2);
                                convAllow=rs2.getInt(3);
                                basicPay=dailyPay*noOfPresents;
                                payroll2+=basicPay+houseRent+convAllow;
                            } 
                        }
                    }
                    return payroll2;
             }catch (Exception e) {
              e.printStackTrace();
              return 0.0;
            } finally {
              try {
                rs.close();
                pstmt.close();
                conn.close();
              } catch (Exception e) {
                e.printStackTrace();
              }
            }
} 

Answer 1

你的问题在这里:

rs2 = pstmt.executeQuery(q2);

您告诉PreparedStatement执行SQL q2,而不是执行先前准备的SQL.这应该只是:

rs2 = pstmt.executeQuery();

这是一个相当常见的错误,主要是由于糟糕的类设计java.sql.Statement 及其子类型造成的.

正如@RMT指出的那样,你在这里犯了同样的错误:

rs1 = pstmt.executeQuery(q1);

这并不重要,因为没有占位符q1,因此SQL按原样执行.但这仍然是错误的.

最后,在将变量重新分配给另一个变量之前,应该考虑调用close()第一个变量.如果不这样做,就有可能发生泄漏.PreparedStatementpstmt