Phi*_*ord 4 sql postgresql group-by aggregate-functions
更新问题:
ERROR: column "Fruits" does not exist
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运行Postgres 7.4(是的,我们正在升级)
为什么我不能按列别名进行排序?想要在ORDER BY中使用"TypeOfFruits",为什么?
SELECT (CASE
WHEN tof."TypeOfFruits" = 'A' THEN 'Apple'
WHEN tof."TypeOfFruits" = 'P' THEN 'Pear'
WHEN tof."TypeOfFruits" = 'G' THEN 'Grapes'
ELSE 'Other' END) AS "Fruits",
SUM(CASE WHEN r.order_date
BETWEEN DATE_TRUNC('DAY', LOCALTIMESTAMP) AND DATE_TRUNC('DAY', LOCALTIMESTAMP) + INTERVAL '1 DAY'
THEN 1 ELSE 0 END) AS daily,
SUM(CASE WHEN r.order_date
BETWEEN DATE_TRUNC('MONTH', LOCALTIMESTAMP) AND DATE_TRUNC('MONTH', LOCALTIMESTAMP) + INTERVAL '1 MONTH'
THEN 1 ELSE 0 END) AS monthly,
SUM(CASE WHEN r.order_date
BETWEEN DATE_TRUNC('YEAR', LOCALTIMESTAMP) AND DATE_TRUNC('YEAR', LOCALTIMESTAMP) + INTERVAL '1 YEAR'
THEN 1 ELSE 0 END) AS yearly,
SUM(CASE WHEN r.order_date >= '01-01-2011 00:00:00' THEN 1 ELSE 0 END) AS lifetime
FROM reports AS r, "TypeOfFruits" AS tof
WHERE r.id = tof."ID"
GROUP BY "Fruits"
ORDER BY CASE
WHEN "Fruits" = 'Apple' THEN 1
WHEN "Fruits" = 'Pear' THEN 2
WHEN "Fruits" = 'Grapes' THEN 3
ELSE 4
END
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截至目前的结果
Fruits;daily;monthly;yearly;lifetime
"Apple";17;1174;3136;3136
"Pear";28;94;94;94
"Grapes";0;191;490;490
"Other";0;2;27;27
"Other";0;0;1;1
"Other";0;0;27;27
"Other";0;6;28;28
"Other";0;58;229;229
"Other";0;3;3;3
"Other";0;0;1;1
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期望的结果将是具有"其他"总计的一行,因此总共四行(x将是总计)
Fruits;daily;monthly;yearly;lifetime
"Apple";17;1174;3136;3136
"Pear";28;94;94;94
"Grapes";0;191;490;490
"Other";x;x;x;x
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您可以使用ORDER BY 1第一个字段来订购,即"Fruits".同样有效GROUP BY
更新
对于订单,而不是case在中order by,在...中创建一个新列说...第二个位置:
(CASE
WHEN "Fruits" = 'Apple' THEN 1
WHEN "Fruits" = 'Pear' THEN 2
WHEN "Fruits" = 'Grapes' THEN 3
ELSE 4 ) as Order
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然后在你ORDER BY 2.