如何创建Parse函数

Med*_*tor 0 java enums

我有班级错误.我有值errorCode.我需要通过errorCode获取字符串.

例, int number = -2;

Errors.Parse(number).toString();
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回报价值 #-2#The username is already in use.

public enum Errors {

        UNKNOWN_ERROR(-1, "Unknown error"), 
        LOGIN_ALREADY_EXISTS(-2, "The username is already in use."),
        LOGIN_OR_PASSWORD_NOT_CORRECT (-3, "LOGIN_OR_PASSWORD_NOT_CORRECT"),
        NULL_POINTER (-4,"Null pointer exception"),
        NOT_CORRECT_DATA (-5,"NOT_CORRECT_DATA");


        private final int errorCode;
        private final String message;

        private Errors(int errorCode, String message) {
            this.errorCode = errorCode;
            this.message = message;
        }

        public int getErrorCode() {
            return errorCode;
        }

        public String getMessage() {
            return message;
        }

        @Override
        public String toString() {
            return "#" + errorCode + "#" + message;
        }
    }
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gou*_*uki 6

您必须循环枚举值,并根据给定的错误代码(num)单独检查每个的错误代码.

就像是:

public static Errors Parse(int num) {

  for(Errors error: Errors.values() ) {
     if (error.getErrorCode() == num ) {
         return error;
     }
  }
  return null;

}
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