mah*_*sif 2 java jpa jpql spring-boot
这是我的查询
select SUM(d.day) as totalDay, SUM(d.month) as totalMonth from record d where d.userId = ?1
Integer getRecod(Long id);
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由于查询未返回整数,因此发生错误。我应该用整数替换什么?
解决方案 1:创建一个包含totalDay 和totalMonth 的模型,并创建一个all args 构造函数。
public class UserDataModel {
Long totalDay;
Long totalMonth;
public UserDataModel(Long totalDay, Long totalMonth) {
this.totalDay = totalDay;
this.totalMonth = totalMonth;
}
//getter and setter
}
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更改您的查询,例如
@Query(value = "select
new com.package.UserDataModel(SUM(d.day) as totalDay, SUM(d.month) as totalMonth)
from Record d where d.userId = ?1 ")
UserDataModel getRecord(Long id);
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解决方案2:使用弹簧投影。创建一个像这样的界面。确保遵循正确的 camcelCase。
public interface UserDataModelV2 {
Long getTotalDay();
Long getTotalMonth();
}
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像这样改变你的方法。
@Query(value = "select " +
" SUM(d.day) as totalDay, SUM(d.month) as totalMonth " +
"from Record d where d.userId = ?1")
List<UserDataModelV2> getRecord(Long id);
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如果你想返回一个HashMap而不是POJO,你可以用hashMap扩展UserDataModel,并在构造函数中将数据放入map中。
public class UserDataModel extends HashMap<String, Object>{
Long totalDay;
Long totalMonth;
public UserDataModel(Long totalDay, Long totalMonth) {
this.totalDay = totalDay;
this.totalMonth = totalMonth;
put("totalDay",totalDay);
put("totalMonth",totalMonth);
}
//getter and setter
}
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或者您可以将解决方案 2 中的 Interface 替换为 Map<Stirng, Object>。
@Query(value = "select " +
" SUM(d.day) as totalDay, SUM(d.month) as totalMonth " +
"from Record d where d.userId = ?1")
List<Map<Stirng, Object>> getRecord(Long id);
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