从url字符串创建模拟HttpServletRequest？

Question

我有一个服务在HttpServletRequest对象上做一些工作,特别是使用request.getParameterMap和request.getParameter来构造一个对象.

我想知道是否有一种直接的方式来获取提供的URL,以字符串的形式,比如说

String url = "http://www.example.com/?param1=value1&param";

并轻松将其转换为HttpServletRequest对象,以便我可以使用单元测试进行测试？或者至少只是为了让request.getParameterMap和request.getParameter正常工作？

Answer 1

Spring 在其spring-test模块中有MockHttpServletRequest.

如果您使用的是maven,则可能需要在pom.xml中添加适当的依赖项.您可以在mvnrepository.com找到spring-test .

Answer 2

最简单的模拟方法HttpServletRequest:

1. 创建一个匿名子类:

   HttpServletRequest mock = new HttpServletRequest ()
   {
       private final Map<String, String[]> params = /* whatever */
   
       public Map<String, String[]> getParameterMap()
       {
           return params;
       }
   
       public String getParameter(String name)
       {
           String[] matches = params.get(name);
           if (matches == null || matches.length == 0) return null;
           return matches[0];
       }
   
       // TODO *many* methods to implement here
   };
   

2. 使用jMock,Mockito或其他一些通用的模拟框架:

   HttpServletRequest mock = context.mock(HttpServletRequest.class); // jMock
   HttpServletRequest mock2 = Mockito.mock(HttpServletRequest.class); // Mockito
   

3. 使用HttpUnit的ServletUnit并且根本不模拟请求.

Answer 3

这是如何使用MockHttpServletRequest:

// given
MockHttpServletRequest request = new MockHttpServletRequest();
request.setServerName("www.example.com");
request.setRequestURI("/foo");
request.setQueryString("param1=value1&param");

// when
String url = request.getRequestURL() + '?' + request.getQueryString(); // assuming there is always queryString.

// then
assertThat(url, is("http://www.example.com:80/foo?param1=value1&param"));