如何使用PHP将整数转换为8位二进制数据？

Question

我需要将整数转换为8位,但打包只能转换为16位二进制数据.我在谷歌搜索,无法获得成功.有人可以帮忙吗？

Answer 1

echo $test = pack('C', 1);

根据格式将参数打包成二进制字符串.

这个功能的想法取自Perl,所有格式代码的工作方式与Perl相同.但是,有一些格式代码丢失,例如Perl的"u"格式代码.

请注意,有符号和无符号值之间的区别仅影响函数unpack(),其中函数pack()为有符号和无符号格式代码提供相同的结果

代码是

a   NUL-padded string
A   SPACE-padded string
h   Hex string, low nibble first
H   Hex string, high nibble first
c   signed char
C   unsigned char
s   signed short (always 16 bit, machine byte order)
S   unsigned short (always 16 bit, machine byte order)
n   unsigned short (always 16 bit, big endian byte order)
v   unsigned short (always 16 bit, little endian byte order)
i   signed integer (machine dependent size and byte order)
I   unsigned integer (machine dependent size and byte order)
l   signed long (always 32 bit, machine byte order)
L   unsigned long (always 32 bit, machine byte order)
N   unsigned long (always 32 bit, big endian byte order)
V   unsigned long (always 32 bit, little endian byte order)
f   float (machine dependent size and representation)
d   double (machine dependent size and representation)
x   NUL byte
X   Back up one byte
@   NUL-fill to absolute position