Nia*_*ker 8 amazon-web-services aws-lambda aws-sam
在 AWS SAM .yaml 模板中,我可以为每个 lambda 函数声明一个内联策略,如下所示:
AWSTemplateFormatVersion: '2010-09-09'
Transform: 'AWS::Serverless-2016-10-31'
Resources:
MyFunction:
Type: 'AWS::Serverless::Function'
Properties:
Handler: index.handler
Runtime: nodejs8.10
CodeUri: 's3://my-bucket/function.zip'
Policies:
- Statement:
- Sid: SSMDescribeParametersPolicy
Effect: Allow
Action:
- ssm:DescribeParameters
Resource: '*'
- Sid: SSMGetParameterPolicy
Effect: Allow
Action:
- ssm:GetParameters
- ssm:GetParameter
Resource: '*'
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但是,如果我希望多个函数共享同一个内联策略文档,我们是否在模板的“全局”部分中声明它?
到目前为止,文档让我相信最干净的方法是创建一个带有附加策略的角色,然后简单地向每个函数声明该角色,如下所示:
AWSTemplateFormatVersion: '2010-09-09'
Transform: 'AWS::Serverless-2016-10-31'
Resources:
MyFunction:
Type: 'AWS::Serverless::Function'
Properties:
Handler: index.handler
Runtime: nodejs8.10
CodeUri: 's3://my-bucket/function.zip'
Role: arn:aws:iam::111111111111:role/SAMPolicy
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有没有办法在模板中声明内联策略并简单地在每个函数上引用它?
如果我希望多个函数共享同一个内联策略文档,我们是否在模板的“全局”部分中声明它? 是的。这是一个例子:
AWSTemplateFormatVersion: '2010-09-09'
Transform: 'AWS::Serverless-2016-10-31'
Globals:
Function:
Policies:
- Statement:
- Sid: SSMDescribeParametersPolicy
Effect: Allow
Action:
- ssm:DescribeParameters
Resource: '*'
- Sid: SSMGetParameterPolicy
Effect: Allow
Action:
- ssm:GetParameters
- ssm:GetParameter
Resource: '*'
Resources:
MyFunction:
Type: 'AWS::Serverless::Function'
Properties:
Handler: index.handler
Runtime: nodejs8.10
CodeUri: 's3://my-bucket/function.zip'
MyOtherFunction:
Type: 'AWS::Serverless::Function'
Properties:
Handler: index.handler
Runtime: nodejs8.10
CodeUri: 's3://my-bucket/other-function.zip'
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