在直方图上添加密度曲线

Question

我可以在 python 中制作直方图，但无法添加密度曲线，我看到许多代码使用不同的方式在直方图上添加密度曲线，但我不确定如何获取我的代码

我添加了密度 = true 但无法在直方图上获得密度曲线

df = pd.DataFrame(np.random.randn(100, 4), columns=list('ABCD'))
X=df['A']

hist, bins = np.histogram(X, bins=10,density=True)
width = 0.7 * (bins[1] - bins[0])
center = (bins[:-1] + bins[1:]) / 2
plt.bar(center, hist, align='center', width=width)
plt.show()

Answer 1

distplot has been removed: removed in a future version of seaborn. Therefore, alternatives are to use histplot and displot.

sns.histplot

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import numpy as np

df = pd.DataFrame(np.random.randn(100, 4), columns=list('ABCD'))
X = df['A']

sns.histplot(X, kde=True, bins=20)
plt.show()

sns.displot

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import numpy as np

df = pd.DataFrame(np.random.randn(100, 4), columns=list('ABCD'))
X = df['A']

sns.displot(X, kde=True, bins=20)
plt.show()

distplot has been removed

Here is an approach using distplot method of seaborn. Also, mentioned in the comments:

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import numpy as np

df = pd.DataFrame(np.random.randn(100, 4), columns=list('ABCD'))
X = df['A']

sns.distplot(X, kde=True, bins=20, hist=True)
plt.show()