Gui*_*i13 4 c++ polymorphism dictionary rtti delete-operator
我有一个问题,使用C++映射来存储指向基类和一些派生类的指针.
让我用一个相当长但很简单的代码来解释:
#include <map>
#include <iostream>
struct foo{ int dummy[4]; };
struct bar{ int additionnal[4]; };
class Base
{
private:
struct foo *_internal_structure;
public:
Base() { _internal_structure = new struct foo; }
~Base()
{
delete _internal_structure;
std::cout << "Base DTOR\n";
}
};
class Derived: public Base
{
private:
struct bar *_additional_structure;
public:
Derived() { _additional_structure = new struct bar; }
~Derived()
{
delete _additional_structure;
std::cout << "Derived DTOR\n";
}
};
int main(int argc, char *argv[])
{
std::map<int, Base*> my_map;
Base *to_add = new Base();
Derived *derived_to_add = new Derived();
my_map[1] = to_add;
my_map[2] = derived_to_add; // works, derived class, but object gets sliced
/// clear hash map ///
std::map<int, Base*>::const_iterator iter;
for(iter = my_map.begin(); iter != my_map.end(); ++iter)
{
delete (*iter).second;
}
return 0;
}
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运行结果:
Base DTOR
Base DTOR
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所以,当我将Derived类指针插入到我的映射中时,底层对象被视为Base类; 所以调用的析构函数是Base类之一,而不是Derived类.Valgrind确认我每次都丢失16个字节.
另外,我不能使用Boost的shared_ptr(我在这里看到了一些提及),我使用的嵌入式架构不支持C++异常和RTTI (在我的例子中,会导致一些未对齐的访问和其他不良内容)(编辑): 不相关的).
你知道我怎么能解决这个问题吗?