从dataURL创建/显示图像

Question

是否可以从POST收到的dataURL创建和显示图片文件？就像是:

<?
$imgstr = $_POST["imgdata"]; //data:image/png;base64,.... etc (it's always PNG)
echo base64_decode($imgstr); // idk what this really does
?>

我无法使用<img>标签来显示它.它需要像"普通"图像文件一样.

Answer 1

是的,试试:

<img alt="Base64 Image" src="data:image/png;base64,{$imgstr}" />

编辑:确保你清理你的$ _POST,所以人们不要插入危险的垃圾......

Answer 2

例如，如果您的输入是

// Red dot graphic, stolen from Wikipedia
$imgstr = 'data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg==';

然后你就可以做你想做的事

// Grab the MIME type and the data with a regex for convenience
if (!preg_match('/data:([^;]*);base64,(.*)/', $imgstr, $matches)) {
    die("error");
}

// Decode the data
$content = base64_decode($matches[2]);

// Output the correct HTTP headers (may add more if you require them)
header('Content-Type: '.$matches[1]);
header('Content-Length: '.strlen($content));

// Output the actual image data
echo $content;
die;