The*_*ter 10
SELECT UserID
FROM tableName
GROUP BY UserID
HAVING COUNT(*) = 24
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更新:查找具有24个不同卡的用户:
SELECT UserID
FROM (
SELECT UserID
FROM tableName
GROUP BY UserID, Card
) rs
GROUP BY UserID
HAVING COUNT(*) = 24
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或者:
SELECT UserID
FROM tableName
GROUP BY UserID
HAVING COUNT(DISTINCT Card) = 24
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