Django 3：过滤字母或非字母的查询集

Question

在我的数据库中，我有一个表，其中包含标题可以以字母或非字母字符开头的项目。例如数字或“@”或“#”。该模型如下所示：

class Items(models.Model):
    title = models.CharField(max_length=255)
    body = models.TextField

在我看来，我想将模型分成两个对象。一个对象包含标题以字母开头的所有项目，另一个对象包含所有其他项目：

class ItemsView(TemplateView):
    template_name = "index.html"

    def get_context_data(self, **kwargs):
        alpha_list = Items.objects.filter(title__startswith=<a letter>)
        other_list = Items.objects.filter(title__startswith=<not a letter>)

        context = {
            "list_a": alpha_list,
            "list_b": other_list
        }

        return context

我一直在查阅文档、stackoverflow和神圣的google，但到目前为止我还没有找到解决方案。

很感谢任何形式的帮助。

Answer 1

您可以使用正则表达式进行过滤（使用 regex101.com 来测试您的正则表达式）并排除以查找其他不以字母开头的项目

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以字母开头：

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alpha_list = Items.objects.filter(title__regex=r\'^[a-zA-Z].*$\')\n

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其他情况：

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other_list = Items.objects.exclude(title__regex=r\'^[a-zA-Z].*$\')\n

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解释：

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/^[a-zA-Z].*$/\n\n^ asserts position at start of the string \n\na-z a single character in the range between a (index 97) and z (index 122) (case sensitive) \n\nA-Z a single character in the range between A (index 65) and Z (index 90) (case sensitive) \n\n.* matches any character (except for line terminators)\n\n* Quantifier \xe2\x80\x94 Matches between zero and unlimited times, as many times as possible, giving back as needed \n\n$ asserts position at the end of the string, or before the line terminator right at the end of the string (if any)\n

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