tri*_*ize 3 kotlin kotlin-exposed
Exposed 0.27.1 是否能够翻译以下 SQL 语句?
SELECT FirstName, LastName,
(SELECT COUNT(O.Id)
FROM "Order" O
WHERE O.CustomerId = C.Id) AS OrderCount
FROM Customer C;
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这是我尝试过的,但不幸的是子查询独立于查询的其余部分工作。
val query = Customer
.leftJoin(Order, { Customer.id }, { Order.customerId })
.slice(
Customer.firstName,
Customer.lastName,
intLiteral(Order
.innerJoin(Customer, { Order.customerId }, { Customer.id })
.slice(Order.id.count())
.select { Order.customerId eq Customer.id }
.first()[Order.id.count()].toInt())//.alias("OrderCount")
)
.selectAll()
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此外,如果可能的话,我如何使用别名从 ResultRow 获取结果?按照这个例子,解决方案似乎是将整个子查询与alias()方法调用存储在单个变量中,但这看起来很难看。有更好的方法吗?
前面的答案不会在 select 子句中生成子查询。下面描述的方式允许它。这是在Exexped 0.36.2上测试的。
下一个示例执行 SQL:
SELECT "groups".id, "groups".name,
(SELECT COUNT(group_members.user_id) FROM group_members
WHERE group_members.group_id = "groups".id) members_count
FROM "groups";
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首先,我们需要一个将 AliasQuery 转换为 Expression 的包装器:
SELECT "groups".id, "groups".name,
(SELECT COUNT(group_members.user_id) FROM group_members
WHERE group_members.group_id = "groups".id) members_count
FROM "groups";
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创建子查询:
class SubQueryExpression<T>(private val aliasQuery : QueryAlias) : Expression<T>() {
override fun toQueryBuilder(queryBuilder: QueryBuilder) {
aliasQuery.describe(TransactionManager.current(), queryBuilder)
}
}
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将子查询包装到表达式:
val membersCount = GroupMembersTable.userId.count()
val subSelect = GroupMembersTable
.slice(membersCount)
.select { GroupMembersTable.groupId eq GroupsTable.id}
val subQuery: QueryAlias = subSelect.alias("members_count")
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进行完整查询:
val membersCountExp = SubQueryExpression<Long>(subQuery)
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执行并读取计算值:
val q = GroupsTable
.slice(GroupsTable.fields + membersCountExp)
.selectAll()
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