如何从字符串数组中删除前几个项目？

Question

我有一个方法,它接受一个字符串数组,并根据长度找到每个项目的平均值.我希望该方法根据offset的值删除数组中的前几个项目.

public static double[] getMovingAverage(String[] priceList, int length, int offset){

    double[] newPriceList = convert(priceList);

    int listLength = newPriceList.length;
    int counter = 0;
    double listsum;
    double[] movingAverage = new double[listLength];

    try{
        for (int aa = 0; aa < listLength-1; aa++){
            listsum = 0;
            for (int bb = 0; bb < length; bb++){
                counter = aa+bb;

                listsum = listsum + newPriceList[counter];
            }
            movingAverage[aa] = listsum / length;
        }
        if (offset>0){

                        //remove first #offset# elements

        }
    }catch(Exception e){
        System.out.println(e);
    }
    return movingAverage;
}

*注意:convert(); 将String []转换为double []

Answer 1

数组在Java中是固定长度的.(您无法更改数组的长度.)

但是,您可以创建一个新数组,其中第一个offset元素很容易删除:

double[] movingAverage = { 0.1, 0.2, 1.1, 1.2 };
int offset = 2;

// print before
System.out.println(Arrays.toString(movingAverage));

// remove first offset elements
movingAverage = Arrays.copyOfRange(movingAverage, offset, movingAverage.length);

// print after
System.out.println(Arrays.toString(movingAverage));

输出:

[0.1, 0.2, 1.1, 1.2]
[1.1, 1.2]