如何在shell脚本中处理ctrl+c?

Sag*_*ole 5 bash shell sigint

我正在尝试在 shell 脚本中处理 ctrl+c 。我的代码在 while 循环中运行,但我从 shell 脚本调用二进制文件并在后台运行它,因此当我想停止二进制文件时,它应该停止。代码如下hello.c

#include <stdio.h>
    
int main()
{
    while(1)
    {
        int n1,n2;
        printf("Enter the first number\n");
        scanf("%d",&n1);
        printf("Enter the second number\n");
        scanf("%d",&n2);
        printf("Entered number are n1 = %d , n2 =%d\n",n1,n2);
    }
}
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下面是我使用的 bash 脚本。

#/i/bin/sh
echo run the hello binary
./hello < in.txt &

trap_ctrlc()
{
    ps -eaf | grep hello | grep -v grep | awk  '{print $2}' | xargs kill -9
    echo trap_ctrlc
    exit
}

trap trap_ctrlc SIGHUP SIGINT SIGTERM
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启动脚本后,hello 二进制文件将持续运行。我已经使用kill -9 pid 命令从其他终端杀死了这个二进制文件。

我尝试过 trap_ctrlc 函数,但它不起作用。如何在shell脚本中处理ctrl+c?

我已经in.txt添加了输入,因此我可以将此文件直接传递给二进制文件。

1
2
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输出:

Enter the first number  
Enter the second number  
Entered number are n1 = 1 , n2 =2  
Enter the first number    
Enter the second number  
Entered number are n1 = 1 , n2 =2   
Enter the first number    
Enter the second number    
Entered number are n1 = 1 , n2 =2  
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而且它持续不断。

Ted*_*gmo 5

更改您的程序,以便检查读取数据是否确实成功:

#include <stdio.h>

int main()
{
    int n1,n2;
    while(1) {
        printf("Enter the first number\n");
        if(scanf("%d",&n1) != 1) return 0;   /* check here */
        printf("Enter the second number\n");
        if(scanf("%d",&n2) != 1) return 0;   /* check here */
        printf("Entered number are n1 = %d , n2 =%d\n",n1,n2);
    }
}
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当输入in.txt耗尽时,它现在将终止。

要制作可多次读取的内容,您可以在脚本中创建一个永远循环(或直到被终止)的in.txt循环。./hello

例子:

#!/bin/bash

# a function to repeatedly print the content in "in.txt"
function print_forever() {
    while [ 1 ];
    do
        cat "$1"
        sleep 1
    done
}

echo run the hello binary
print_forever in.txt | ./hello &
pid=$!
echo "background process $pid started"

trap_ctrlc() {
    kill $pid
    echo -e "\nkill=$? (0 = success)\n"
    wait $pid
    echo "wait=$? (the exit status from the background process)"
    echo -e "\n\ntrap_ctrlc\n\n"
}

trap trap_ctrlc INT

# wait for all background processes to terminate
wait
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可能的输出:

$ ./hello.sh
run the hello binary
background process 262717 started
Enter the first number
Enter the second number
Entered number are n1 = 1 , n2 =2
Enter the first number
Enter the second number
Entered number are n1 = 1 , n2 =2
Enter the first number
^C
kill=0 (0 = success)

wait=143 (the exit status from the background process)


trap_ctrlc
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另一种选择是在wait中断后杀死孩子:

#!/bin/bash

function print_forever() {
    while [ 1 ];
    do
        cat "$1"
        sleep 1
    done
}
 
echo run the hello binary
print_forever in.txt | ./hello &
pid=$!
echo "background process $pid started"
 
trap_ctrlc() {
    echo -e "\n\ntrap_ctrlc\n\n"
}
 
trap trap_ctrlc INT
 
# wait for all background processes to terminate
wait
echo first wait=$?
kill $pid
echo -e "\nkill=$? (0 = success)\n"
wait $pid
echo "wait=$? (the exit status from the background process)"`
``
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