主视图是一个简单的分页ListView,我想添加一个搜索表单.
我认为这样的事情可以解决问题:
class MyListView(ListView, FormView):
form_class = MySearchForm
success_url = 'my-sucess-url'
model = MyModel
# ...
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但显然我弄错了......我在官方文档中找不到如何做到这一点.
建议?
小智 31
这些答案帮助我引导我朝着正确的方向前进.谢谢你们.
对于我的实现,我需要一个表单视图,在get和post上返回ListView.我不喜欢重复get函数的内容,但需要进行一些更改.现在,使用self.form也可以从get_queryset获取该表单.
from django.http import Http404
from django.utils.translation import ugettext as _
from django.views.generic.edit import FormMixin
from django.views.generic.list import ListView
class FormListView(FormMixin, ListView):
def get(self, request, *args, **kwargs):
# From ProcessFormMixin
form_class = self.get_form_class()
self.form = self.get_form(form_class)
# From BaseListView
self.object_list = self.get_queryset()
allow_empty = self.get_allow_empty()
if not allow_empty and len(self.object_list) == 0:
raise Http404(_(u"Empty list and '%(class_name)s.allow_empty' is False.")
% {'class_name': self.__class__.__name__})
context = self.get_context_data(object_list=self.object_list, form=self.form)
return self.render_to_response(context)
def post(self, request, *args, **kwargs):
return self.get(request, *args, **kwargs)
class MyListView(FormListView):
form_class = MySearchForm
model = MyModel
# ...
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我一直在寻找合适的解决方案.但我找不到任何必须提出自己的.
views.py
class VocationsListView(ListView):
context_object_name = "vocations"
template_name = "vocations/vocations.html"
paginate_by = 10
def get_queryset(self):
get = self.request.GET.copy()
if(len(get)):
get.pop('page')
self.baseurl = urlencode(get)
model = Vocation
self.form = SearchForm(self.request.GET)
filters = model.get_queryset(self.request.GET)
if len(filters):
model = model.objects.filter(filters)
else:
model = model.objects.all()
return model
def get_context_data(self):
context = super(VocationsListView, self).get_context_data()
context['form'] = self.form
context['baseurl']= self.baseurl
return context
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models.py
class Vocation(models.Model):
title = models.CharField(max_length = 255)
intro = models.TextField()
description = models.TextField(blank = True)
date_created = models.DateTimeField(auto_now_add = True)
date_modified = models.DateTimeField(auto_now = True)
created_by = models.ForeignKey(User, related_name = "vocation_created")
modified_by = models.ForeignKey(User, related_name = "vocation_modified")
class Meta:
db_table = "vocation"
@property
def slug(self):
return defaultfilters.slugify(self.title)
def __unicode__(self):
return self.title
@staticmethod
def get_queryset(params):
date_created = params.get('date_created')
keyword = params.get('keyword')
qset = Q(pk__gt = 0)
if keyword:
qset &= Q(title__icontains = keyword)
if date_created:
qset &= Q(date_created__gte = date_created)
return qset
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所以基本上我将这段代码添加到每个模型类中,我想在其中实现搜索功能.这是因为必须明确准备每个模型的过滤器
@staticmethod
def get_queryset(params):
date_created = params.get('date_created')
keyword = params.get('keyword')
qset = Q(pk__gt = 0)
if keyword:
qset &= Q(title__icontains = keyword)
if date_created
qset &= Q(date_created__gte = date_created)
return qset
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它准备我用来从模型中检索数据的qset过滤器
在 Django 2.2 中你可以这样做(至少在使用 -request 时效果很好get):
from django.views.generic import ListView
from django.views.generic.edit import FormMixin
from .models import MyModel
from .forms import MySearchForm
class ListPageView(FormMixin, ListView):
template_name = 'property_list.html'
model = MyModel
form_class = MySearchForm
queryset = MyModel.objects.all()
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FormMixin在 之前使用ListView. SearchForm如果你想在 a 中使用,TemplateView你可以这样做:
from django.views.generic.base import TemplateView
from django.views.generic.edit import FormMixin
from .models import MyModel
from .forms import MySearchForm
class HomePageView(FormMixin, TemplateView):
template_name = 'home.html'
form_class = MySearchForm
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