所以我有一个如下所示的 JSON:
{
"name": "customer",
"properties": [
{
"name": "id",
"type": "int",
"value": 32
},
{
"name": "name",
"type": "string",
"value": "John"
}
]
}
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目前我正在反序列化到这组结构:
#[derive(Serialize, Deserialize, Debug)]
struct Customer {
name: String,
properties: Vec<Property>,
}
#[derive(Serialize, Deserialize, Debug)]
#[serde(tag = "name", content = "value")]
enum Property {
#[serde(rename = "id")]
Id(i32),
#[serde(rename = "name")]
Name(String),
}
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但为了避免每次我想访问一个属性时都要处理枚举匹配,我想将其反序列化为如下所示的结构:
struct Customer {
name: String,
properties: Properties,
}
struct Properties {
id: i32, // will be 32 as in the object containing the name "id".
name: String, // will be John as in the object containing the name "name".
}
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这是serde图书馆以某种方式允许的吗?如果是这样,您能提供一个如何实现这一目标的例子吗?
请注意,我不能弄乱实际的 json 结构,所以我对任何需要它的解决方案不感兴趣。
感谢edkeveked 的回答,我设法找到了一个非常适合我的需求的解决方案。
基本上,我重新安排了反序列化器以循环整个属性数组,并尝试将其中的每个对象与枚举变体相匹配。我喜欢这个,因为我可以在将来轻松映射新的属性,并且它在类型方面感觉更灵活。
无论如何,这是它的代码:
extern crate serde;
extern crate serde_json;
#[macro_use]
extern crate serde_derive;
use serde::de::{Deserializer, SeqAccess, Visitor};
use std::fmt;
#[derive(Serialize, Deserialize, Debug)]
struct Customer {
name: String,
#[serde(deserialize_with = "parse_property")]
properties: CustomerProps,
}
#[derive(Default, Serialize, Deserialize, Debug)]
struct CustomerProps {
id: i32,
name: String,
}
#[derive(Serialize, Deserialize, Debug)]
#[serde(tag = "name", content = "value")]
enum Property {
#[serde(rename = "id")]
Id(i32),
#[serde(rename = "name")]
Name(String),
}
fn parse_property<'de, D>(deserializer: D) -> Result<CustomerProps, D::Error>
where
D: Deserializer<'de>,
{
struct PropertyParser;
impl<'de> Visitor<'de> for PropertyParser {
type Value = CustomerProps;
fn expecting(&self, formatter: &mut fmt::Formatter) -> fmt::Result {
formatter.write_str("[u64, f32, usize]")
}
fn visit_seq<A: SeqAccess<'de>>(self, mut seq: A) -> Result<Self::Value, A::Error> {
let mut prop = CustomerProps {
..Default::default()
};
while let Some(tmp) = seq.next_element::<Property>()? {
match tmp {
Property::Id(id) => prop.id = id,
Property::Name(name) => prop.name = name,
}
}
Ok(prop)
}
}
deserializer.deserialize_any(PropertyParser {})
}
fn main() {
let data = r#"{
"name": "customer",
"properties": [
{
"name": "id",
"type": "int",
"value": 32
},
{
"name": "name",
"type": "string",
"value": "John"
}
]
}"#;
let p: Customer = serde_json::from_str(data).unwrap();
println!("Please call {} at the number {} {}", p.name, p.properties.id, p.properties.name);
}
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