如何将 Vuex mapGetters 与 Vue 3 SFC 脚本设置语法结合使用?

ux.*_*eer 13 vuex vuejs3 vue-composition-api vuex4 vue-script-setup

我正在将组件从常规 Vue 3 Composition API 重构为脚本设置语法。初始点:

<script lang="ts">
import { defineComponent, computed } from 'vue';
import { mapGetters } from 'vuex';

export default defineComponent({
  name: 'MyCoolBareComponent',
  computed: {
    ...mapGetters('auth', ['isAdmin']),
  },
});
</script>
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当前Vue v3 迁移文档SFC Composition API Syntax Sugar (<脚本设置>),链接到此 RFC 页面:https://github.com/vuejs/rfcs/pull/182

使用计算反应性属性只有一个示例:

export const computedMsg = computed(() => props.msg + '!!!')
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由于当前没有可用的 Vuex 4 文档提到<scrip setup>,所以我仍然不清楚在使用此语法时应该如何使用?mapGetters或者使用 Vuex 4 解决这个问题的正确方法是什么?

Mar*_*der 15

tldr:向下滚动到最终结果

现在有更好的文档,简单的答案是:您不需要mapGetters,但可以自己实现。

https://next.vuex.vuejs.org/guide/composition-api.html#accessing-state-and-getters

<script setup>
import { computed } from 'vue'
import { useStore } from 'vuex'

const store = useStore()

const count = computed(() => store.getters.count)
</script>
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如果你有很多 getter 想要变成“计算属性”,你可以使用像这样“直观”的东西:

const { countIsOdd, countIsEven } = Object.fromEntries(Object.keys(store.getters).map(getter => [getter, computed(() => store.getters[getter])]))
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将其放入一个函数中,它看起来甚至很不错。

const mapGetters = (getters) => {
  return Object.fromEntries(Object.keys(getters).map(getter => [getter, computed(() => getters[getter])]))
}

const { countIsOdd, countIsEven } = mapGetters(store.getters)
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将该函数放入文件中并将其导出为模块......

// lib.js
import { computed } from 'vue'
import { useStore } from 'vuex'

const mapGetters = () => {
  const store = useStore()
  return Object.fromEntries(Object.keys(store.getters).map(getter => [getter, computed(() => store.getters[getter])]))
}

export { mapGetters }
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...您可以轻松地在所有组件中使用它。

// components/MyComponent.vue
<script setup>
import { mapGetters } from '../lib'

const { countIsOdd, countIsEven } = mapGetters()
</script>
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最后结果:

这是我想出的最终 lib.js:

import { computed } from 'vue'
import { useStore } from 'vuex'

const mapState = () => {
  const store = useStore()
  return Object.fromEntries(
    Object.keys(store.state).map(
      key => [key, computed(() => store.state[key])]
    )
  )
}

const mapGetters = () => {
  const store = useStore()
  return Object.fromEntries(
    Object.keys(store.getters).map(
      getter => [getter, computed(() => store.getters[getter])]
    )
  )
}

const mapMutations = () => {
  const store = useStore()
  return Object.fromEntries(
    Object.keys(store._mutations).map(
      mutation => [mutation, value => store.commit(mutation, value)]
    )
  )
}

const mapActions = () => {
  const store = useStore()
  return Object.fromEntries(
    Object.keys(store._actions).map(
      action => [action, value => store.dispatch(action, value)]
    )
  )
}

export { mapState, mapGetters, mapMutations, mapActions }
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在组件中使用它看起来像这样:

<template>
  Count: {{ count }}
  Odd: {{ counterIsOdd }}
  Even: {{ counterIsEven }}
  <button @click="countUp">count up</button>
  <button @click="countDown">count down</button>
  <button @click="getRemoteCount('https://api.countapi.xyz')">
    get remote count
  </button>
</template>

<script setup>
import { mapState, mapGetters, mapMutations, mapActions } from '../lib'

// computed properties
const { count } = mapState()
const { countIsOdd, countIsEvent } = mapGetters()

// commit/dispatch functions
const { countUp, countDown } = mapMutations()
const { getRemoteCount } = mapActions()
</script>
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对此的任何反馈将不胜感激。


ux.*_*eer 4

到目前为止,这个语法似乎有效。然而,我希望 Vuex 能够开发一种更干净的方法来公开模板的计算 getter。

如果您知道更好的方法,我们很乐意听到!

<script setup lang="ts">
import { mapGetters } from 'vuex';

export const name = 'MyCoolBareComponent';

export default {
  computed: {
    ...mapGetters('user', ['profile', 'roles']),
  },
};
</script>
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