如何在 Flutter Web 中捕获 OAuth2 令牌？

Question

此依赖项据称支持 Web，但缺少侦听回调和检索令牌的实现。在过去三天中仔细研究之后，一些人建议它可以使用 dart:html 库以及 onMessage 和 postMessage 函数来工作。

这是我的设置：

import 'dart:html' as html;
import 'package:http/http.dart' as http;
import 'package:flutter/material.dart';
import 'package:oauth2/oauth2.dart' as oauth2;
import 'package:url_launcher/url_launcher.dart';

class AuthYoutube {
var httpClient = http.Client();
  Future<oauth2.Client> getClient() async {
    var grant = new oauth2.AuthorizationCodeGrant(
        CLIENT_ID, AUTH_DOMAIN, AUTH_TOKEN,
        secret: secret);
    var authorizationUrl =
        grant.getAuthorizationUrl(REDIRECT_URI, scopes: scopes);

    html.window.open(authorizationUrl.toString(), "open");
    Completer<LinkedHashMap<dynamic, dynamic>> completer = Completer();
    html.window.onMessage.listen((event) async {
      completer.complete(event.data as LinkedHashMap<dynamic, dynamic>);
    });
    Uri responseUri;
    completer.future.then((value) {
      responseUri = Uri.parse(value.toString());
      return grant.handleAuthorizationResponse(responseUri.queryParameters);
    });
  }

并将单独的路由设置为回调 URL：

class Special extends StatelessWidget {
  static String route = "/special";
  @override
  Widget build(BuildContext context) {
    final loc = Uri.parse(html.window.location.href);
    final code = loc.queryParameters["code"];
    print("code $code");
    html.window.postMessage(code, html.window.location.origin);
    return Text("All done");
  }
}

最终发生的事情是最后一步的地址栏中显示了身份验证令牌。我可以在那里看到它之后?code=，但它没有被打印出来。该listen方法在整个流程中被触发 5-6 次（同时在另一个窗口中单击“允许”）。在控制台中，我只收到一个错误：

Uncaught (in promise) Error: Bad state: Future already completed
    at Object.throw_ [as throw] (errors.dart:212)
    at _AsyncCompleter.new.complete (future_impl.dart:43)
    at authYT.dart:41
    at Generator.next (<anonymous>)
    at runBody (async_patch.dart:84)
    at Object._async [as async] (async_patch.dart:123)
    at authYT.dart:40
    at Object._checkAndCall (operations.dart:324)
    at Object.dcall (operations.dart:329)
    at html_dart2js.dart:37246

Answer 1

您可以通过 URL 在 onGenerateRoute 方法中捕获访问令牌。

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Here\xe2\x80\x99s 是正确执行此操作的博客链接： https: //aws.plainenglish.io/oauth2-in-flutter-web-using-aws-cognito-f7051be92bdf

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