使用Python中的BeautifulSoup解析html

lum*_*ere 3 html python beautifulsoup

我写了一些代码来解析html,但结果并不是我想要的:

import urllib2
html = urllib2.urlopen('http://dummy').read()
from BeautifulSoup import BeautifulSoup
soup = BeautifulSoup(html)
for definition in soup.findAll('span', {"class":'d'}):
definition = definition.renderContents()
print "<meaning>", definition
for exampleofuse in soup.find('span',{"class":'x'}):
    print "<exampleofuse>", exampleofuse, "<exampleofuse>"
print "<meaning>"
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当class属性为"d"或"x"然后获取字符串时,有什么方法吗?

以下html代码是我要解析的:

<span class="d">calculated by adding several amounts together</span>
<span class="x">an average rate</span>
<span class="x">at an average speed of 100 km/h</span>
<span class="d">typical or normal</span>
<span class="x">average intelligence</span>
<span class="x">20 pounds for dinner is average</span>
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然后,这是我想要的结果:

<definition>calculated by adding several amounts together
    <example_of_use>an average rate</example_of_use>
    <example_of_use>at an average speed of 100 km/h</example_of_use>
</definition>
<definition>typical or normal
    <example_of_use>average intelligence</example_of_use>
    <example_of_use>20 pounds for dinner is average</example_of_use>
</definition>
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rol*_*one 5

是的,你可以获得html中的所有跨度,然后每次检查一个"d"或"x"类,如果是,则打印它们.

这样的事情可能会起作用(未经测试):

for span in soup.findAll('span'):
    if span.find("span","d").string:
        print "<definition>" + span.find("span","d").string + "</definition>"
    elif span.find("span","x").string:
        print "<example>" + span.find("span","x").string + "</example>"
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