Joh*_*ohn 104 javascript post xmlhttprequest http-post httpwebrequest
有没有办法使用post方法发送数据而没有表单,没有刷新页面只使用纯Javascript(不是jQuery $.post())？也许是httprequest或其他东西,现在找不到它.
Joh*_*n G 107
您可以发送它并将数据插入正文:
var xhr = new XMLHttpRequest();
xhr.open("POST", yourUrl, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
value: value
}));
顺便说一下,获取请求:
var xhr = new XMLHttpRequest();
// we defined the xhr
xhr.onreadystatechange = function () {
if (this.readyState != 4) return;
if (this.status == 200) {
var data = JSON.parse(this.responseText);
// we get the returned data
}
// end of state change: it can be after some time (async)
};
xhr.open('GET', yourUrl, true);
xhr.send();
Jam*_*ice 50
您可以XMLHttpRequest按如下方式使用该对象:
xhr.open("POST", url, true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
xhr.send(someStuff);
该代码将发布someStuff到url.只需确保在创建XMLHttpRequest对象时,它将与跨浏览器兼容.有无数的例子说明如何做到这一点.
Con*_*oad 41
[2017年撰写时的新内容] Fetch API旨在使GET请求变得简单,但它也可以进行POST.
let data = {element: "barium"};
fetch("/post/data/here", {
method: "POST",
body: JSON.stringify(data)
}).then(res => {
console.log("Request complete! response:", res);
});
如果你像我一样懒(或者只是喜欢快捷方式/助手):
window.post = function(url, data) {
return fetch(url, {method: "POST", body: JSON.stringify(data)});
}
// ...
post("post/data/here", {element: "osmium"});
Des*_*eba 26
你可以使用 XMLHttpRequest, fetch API, ...
如果你想使用 XMLHttpRequest 你可以执行以下操作
var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
name: "Deska",
email: "deska@gmail.com",
phone: "342234553"
}));
xhr.onload = function() {
var data = JSON.parse(this.responseText);
console.log(data);
};
或者如果你想使用 fetch API
fetch(url, {
method:"POST",
body: JSON.stringify({
name: "Deska",
email: "deska@gmail.com",
phone: "342234553"
})
}).then(result => {
// do something with the result
console.log("Completed with result:", result);
}).catch(err => {
// if any error occured, then catch it here
console.error(err);
});
per*_*oud 24
此外,REST风格让你得到的数据回从POST请求.
JS(放入static/hello.html通过Python提供):
<html><head><meta charset="utf-8"/></head><body>
Hello.
<script>
var xhr = new XMLHttpRequest();
xhr.open("POST", "/postman", true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
value: 'value'
}));
xhr.onload = function() {
console.log("HELLO")
console.log(this.responseText);
var data = JSON.parse(this.responseText);
console.log(data);
}
</script></body></html>
Python服务器(用于测试):
import time, threading, socket, SocketServer, BaseHTTPServer
import os, traceback, sys, json
log_lock = threading.Lock()
log_next_thread_id = 0
# Local log functiondef
def Log(module, msg):
with log_lock:
thread = threading.current_thread().__name__
msg = "%s %s: %s" % (module, thread, msg)
sys.stderr.write(msg + '\n')
def Log_Traceback():
t = traceback.format_exc().strip('\n').split('\n')
if ', in ' in t[-3]:
t[-3] = t[-3].replace(', in','\n***\n*** In') + '(...):'
t[-2] += '\n***'
err = '\n*** '.join(t[-3:]).replace('"','').replace(' File ', '')
err = err.replace(', line',':')
Log("Traceback", '\n'.join(t[:-3]) + '\n\n\n***\n*** ' + err + '\n***\n\n')
os._exit(4)
def Set_Thread_Label(s):
global log_next_thread_id
with log_lock:
threading.current_thread().__name__ = "%d%s" \
% (log_next_thread_id, s)
log_next_thread_id += 1
class Handler(BaseHTTPServer.BaseHTTPRequestHandler):
def do_GET(self):
Set_Thread_Label(self.path + "[get]")
try:
Log("HTTP", "PATH='%s'" % self.path)
with open('static' + self.path) as f:
data = f.read()
Log("Static", "DATA='%s'" % data)
self.send_response(200)
self.send_header("Content-type", "text/html")
self.end_headers()
self.wfile.write(data)
except:
Log_Traceback()
def do_POST(self):
Set_Thread_Label(self.path + "[post]")
try:
length = int(self.headers.getheader('content-length'))
req = self.rfile.read(length)
Log("HTTP", "PATH='%s'" % self.path)
Log("URL", "request data = %s" % req)
req = json.loads(req)
response = {'req': req}
response = json.dumps(response)
Log("URL", "response data = %s" % response)
self.send_response(200)
self.send_header("Content-type", "application/json")
self.send_header("content-length", str(len(response)))
self.end_headers()
self.wfile.write(response)
except:
Log_Traceback()
# Create ONE socket.
addr = ('', 8000)
sock = socket.socket (socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
sock.bind(addr)
sock.listen(5)
# Launch 100 listener threads.
class Thread(threading.Thread):
def __init__(self, i):
threading.Thread.__init__(self)
self.i = i
self.daemon = True
self.start()
def run(self):
httpd = BaseHTTPServer.HTTPServer(addr, Handler, False)
# Prevent the HTTP server from re-binding every handler.
# https://stackoverflow.com/questions/46210672/
httpd.socket = sock
httpd.server_bind = self.server_close = lambda self: None
httpd.serve_forever()
[Thread(i) for i in range(10)]
time.sleep(9e9)
控制台日志(chrome):
HELLO
hello.html:14 {"req": {"value": "value"}}
hello.html:16
{req: {…}}
req
:
{value: "value"}
__proto__
:
Object
控制台日志(firefox):
GET
http://XXXXX:8000/hello.html [HTTP/1.0 200 OK 0ms]
POST
XHR
http://XXXXX:8000/postman [HTTP/1.0 200 OK 0ms]
HELLO hello.html:13:3
{"req": {"value": "value"}} hello.html:14:3
Object { req: Object }
控制台日志(Edge):
HTML1300: Navigation occurred.
hello.html
HTML1527: DOCTYPE expected. Consider adding a valid HTML5 doctype: "<!DOCTYPE html>".
hello.html (1,1)
Current window: XXXXX/hello.html
HELLO
hello.html (13,3)
{"req": {"value": "value"}}
hello.html (14,3)
[object Object]
hello.html (16,3)
{
[functions]: ,
__proto__: { },
req: {
[functions]: ,
__proto__: { },
value: "value"
}
}
Python日志:
HTTP 8/postman[post]: PATH='/postman'
URL 8/postman[post]: request data = {"value":"value"}
URL 8/postman[post]: response data = {"req": {"value": "value"}}
小智 10
有一种简单的方法可以包装数据并将其发送到服务器，就像使用POST. 你可以使用FormData对象来做到这一点，如下所示：
data = new FormData()
data.set('Foo',1)
data.set('Bar','boo')
let request = new XMLHttpRequest();
request.open("POST", 'some_url/', true);
request.send(data)
现在您可以像处理常规 HTML 表单一样在服务器端处理数据。
附加信息
建议您在发送 FormData 时不要设置 Content-Type 标头，因为浏览器会处理这些。
您是否知道 JavaScript 具有创建表单和提交表单的内置方法和库？
我在这里看到很多回复都要求使用 3rd 方库，我认为这有点矫枉过正。
我会在纯 Javascript 中执行以下操作：
<script>
function launchMyForm()
{
var myForm = document.createElement("FORM");
myForm.setAttribute("id","TestForm");
document.body.appendChild(myForm);
// this will create a new FORM which is mapped to the Java Object of myForm, with an id of TestForm. Equivalent to: <form id="TestForm"></form>
var myInput = document.createElement("INPUT");
myInput.setAttribute("id","MyInput");
myInput.setAttribute("type","text");
myInput.setAttribute("value","Heider");
document.getElementById("TestForm").appendChild(myInput);
// This will create an INPUT equivalent to: <INPUT id="MyInput" type="text" value="Heider" /> and then assign it to be inside the TestForm tags.
}
</script>
这样 (A) 你不需要依赖 3rd 方来完成这项工作。(B) 所有浏览器都内置了它，(C) 更快，(D) 它可以工作，请随意尝试。
我希望这有帮助。H
这里最受欢迎的答案没有显示如何从 POST 获取数据。此外，当将数据发送到最新版本的 NodeJS 时，流行的“获取”解决方案在最新版本的 Chrome 中不起作用，除非您传递标头并解开 response.json() 承诺。此外，流行的答案不使用 async/await。
这是我能想到的最干净、最完整的解决方案。
async function postJsonData(jsonObject) {
const response = await fetch("/echo", {
method: "POST",
headers: {'Content-Type': 'application/json'},
body: JSON.stringify(jsonObject)
});
const actualResponse = await response.json();
}
如果您只需要POST数据并且不需要服务器响应，则最短的解决方案是使用navigator.sendBeacon()：
const data = JSON.stringify({
example_1: 123,
example_2: 'Hello, world!',
});
navigator.sendBeacon('example.php', data);
| 归档时间： |
|
| 查看次数： |
232192 次 |
| 最近记录： |