有3个表:
电影(id,title,yr,score,votes,director)actor(id,name)cast(movieid,actorid,ord)
问:"约翰特拉沃尔塔"最繁忙的几年.显示他每年制作的电影数量.
答:我的尝试是语法上的.为什么?
select yr, count(*)
from
(actor join casting
on (actor.id = casting.actorid)
join
on (movie.id = casting.movieid)
group by yr
having actor.name='John Travolta'
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joinwhere不having试试这个:
select yr, count(*)
from actor
join casting on actor.id = casting.actorid
join movie on movie.id = casting.movieid -- you were missing table name "movie"
where actor.name='John Travolta' -- "where", not "having"
group by yr
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另请注意我使用的一致格式.如果使用良好的格式,则更容易发现语法错误
FYI having用于聚合函数,例如having count(*) > 3
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