Ade*_*nut 5 javascript destructuring ecmascript-6 es6-modules
我想澄清一件事。
在React中,我们经常使用import {useState, useEffect} from 'react'.
我们可以将其视为 ES6 中的解构功能吗?
查看react src代码
export {
useState,
// ...
Children,
// ....
} from './src/React';
Run Code Online (Sandbox Code Playgroud)
所以你可以直接从这个对象导入,例如
import { useState } from 'react'
// you can also rename it to anything you want
import { useState as useReactState } from 'react'
Run Code Online (Sandbox Code Playgroud)
或者您可以获取默认导出的整个对象,然后引用它useState
import React from 'react'
// use React.useState
// renaming will be like assigning a function to another variable e.g.
const useReactState = React.useState
// you also get all exported types and modules and wrap them up in React name
import * as React from 'react'
Run Code Online (Sandbox Code Playgroud)
Babel 转译输出
import React from 'react'
const Component = () => {
const [state, setState] = React.useState()
}
// will transpile to something like
var Component = function Component() {
var _React$useState = _react["default"].useState(),
_React$useState2 = _slicedToArray(_React$useState, 2),
state = _React$useState2[0],
setState = _React$useState2[1];
};
Run Code Online (Sandbox Code Playgroud)
另一方面
import {useState} from 'react'
const Component = () => {
const [state, setState] = useState()
}
// will transpile to something like
var Component = function Component() {
var _useState = (0, _react.useState)(),
_useState2 = _slicedToArray(_useState, 2),
state = _useState2[0],
setState = _useState2[1];
};
Run Code Online (Sandbox Code Playgroud)
对象销毁和导入/导出语句有一些相似之处,但最终并不相同,两者都有各自不同的特点
| 归档时间: |
|
| 查看次数: |
1484 次 |
| 最近记录: |